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babunello [35]
3 years ago
10

What is the approximate volume of a cylinder with a height of 2 ft and a radius of 6 ft?

Mathematics
1 answer:
Lisa [10]3 years ago
7 0
To find the volume of a cylinder, first find the area of its base which is              πr² = (3.14)(6)²  = 113.04     Then you would multiply that by the height of the cylinder   113.04 x 2 = 226.08 ft
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I need to find the limit
Digiron [165]
For x=\dfrac{1}{2} the function is undefined.

\displaystyle
\lim_{x\to\tfrac{1}{2}^-} x\sec (\pi x)=\infty\\
\lim_{x\to\tfrac{1}{2}^+} x\sec (\pi x)=-\infty\\\\
\lim_{x\to\tfrac{1}{2}^-}x\sec (\pi x)\not = \lim_{x\to\tfrac{1}{2}^+}x\sec (\pi x)

So, the limit doesn't exist.
8 0
3 years ago
601.584 to the nearest tenth
son4ous [18]
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7 0
2 years ago
Rearrange each of the following formula so the pronumeral in the bracket becomes the subject of the equation
MakcuM [25]

Answer:

y = 9 - 3x

Step-by-step explanation:

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y = 9 - 3x

6 0
2 years ago
Patel made a rectangular garden in his family's backyard. 24 ft What is the perimeter of the garden? A 336 feet B 76 feet C 48 f
ololo11 [35]

Answer:

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Step-by-step explanation:

add all those sides up because it is just the perimeter

7 0
3 years ago
Read 2 more answers
Please help me with this question
kiruha [24]

Answer:

First Row: Given

Second Row: Definition of Regular Polygon

Third Row: Definition of Congruence In Terms of Rigid Motion

Fourth Row: Definition of Regular Polygon

Fifth Row: SAS Triangle Congruence Theorem

Sixth Row: CPCTC

Step-by-step explanation:

This is a basic proof in order to prove that verticals of a polygon are congruent. This should be the right answer since it's the only thing that makes sense to me. I really hope this helps you and thanks for being patient! I've been doing geometry and we have to prove everything we claim in a proof just like this one. However, there was one I kind of guessed on (the third row), but I think it should be correct! I saw from the photo that you have a check answer on the bottom of your screen. Just check the answers that I have for you now and if something is wrong, then we can continue talking about it! Hope this helps!! :)

3 0
3 years ago
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