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Aleksandr-060686 [28]
3 years ago
14

FIRST TO ANSWER, would be marked as brainliest:)

Mathematics
2 answers:
kherson [118]3 years ago
7 0

Your answer is B) 100cos 40° + 100sin 40° ≈ 141 yards. Hope I Helped

boyakko [2]3 years ago
3 0

Answer:

100 Cos 40° + 100 Sin 40° ≈ 141 yards

Step-by-step explanation:

From the diagram, side x is adjacent to the angle 40° while side y is the opposite to that same angle

This means that;

Cos 40° = x/100

x = 100 Cos 40°

Sin 40° = y/100

y = 100 Sin 40°

Therefore, total distance walked = x + y

                         "                             = 100 Cos 40° + 100 Sin 40° ≈ 141 yards

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Let R(ABCDE) be a relation in Boyce-Codd Normal Form (BCNF). If AC is the only key for R, identify each of these FD's from the f
Goshia [24]

Given that R(ABCDE) is in Boyce-Codd normal form.

And AB is the only key for R.

Definition

A relational nontrivial Schema R is in BCNF if FD (X-A) holds in R, Super key of R. whenever then X is

a

Given that AB is the only key for R.

ABC E (Yes).

check if ABC is a Super key. AB is a key, ABC is A B C E is in BONE a super key.

2) ACE B

(NO). no Check if ACE As there is ACE is not a Super key? AB in Super key. ACE.

ACE B

is

Boyce-Codd Normal Form not in BENE (NO)

3) ACDE → B           (NO)

check if is a super key. ACDE

As ACDE there is not any AB Tn ACDE. a super key.

ACDEB is not in BCNF.

4) BS → C → (NO)

As there is no AB in BC ~. B(→ not in BCNF

BC is not a super key.

5) ABDE (Yes).

Since AB is a key.

ABO TS a super key.

.. ABDE → E is in BCNF

Let R(ABCDE) be a relation in Boyce-Codd Normal Form (BCNF). If AB is the only key for R, identify each of these FDs from the following list. Answer Yes or No and explain your answer to receive points.

1. ABC E

2. ACE B

3. ACDE B

4. BC C

5. ABD E

Learn more about Boyce-Codd Normal Form at

brainly.com/question/14299832

#SPJ4

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