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Debora [2.8K]
3 years ago
14

A set of 4 consecutive even integers sums to 388

Mathematics
1 answer:
ipn [44]3 years ago
7 0

Answer:

<h3>          94, 96, 98, 100</h3>

Step-by-step explanation:

If z is any integer then 2z is even number

The consecutive even numbers following 2z would be:

2z+2

2z+2+2 = 2z+4

2z+4+2 = 2z+6

the sum is 388 so:

2z + 2z+2 + 2z+4 + 2z+6 = 388

8z + 12 = 388

8z = 376

2z = 94

2z+2 = 94+2 = 96

2z+4 = 94 + 4 = 98

2z+6 = 94+6 = 100

Check:

94+96+98+100 = 190+198 = 388

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