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baherus [9]
3 years ago
12

4: A school has 314 boys & 310 girls. If they are to be grouped into equal classes of 26 each , how many classes will there

be?
5: Jim worked 48 weeks last year. Each week he worked 38 hours. If he worked an additional 240 hours of overtime, how many hours did he work in all?

please show your work!! and thank you!!
Mathematics
1 answer:
kherson [118]3 years ago
6 0

4: A school has 314 boys & 310 girls. If they are to be grouped into equal classes of 26 each , how many classes will there be?

314 boys + 310 girls = 624

If they are grouped into classes of 26 students each, how many class will there be?

130 students = 5 classes

Therefore

260 students = 10 classes

260 x 2 = 520 = 20 classes

26 x 24 = 624

Number of classes = 24

Question 5).

Jim worked 48 weeks last year. Each week he worked 38 hours. If he worked an additional 240 hours of overtime, how many hours did he work in all?

Solution:

48 weeks

24hrs × 7 = 168hrs

168 x 48 = 8,064

Additional 240hrs

= 168hrs = 7 days (a week)

240hrs - 168 = 72 (3days)

168 + 72

= 240hrs + 8, 064

= 8, 304 hrs

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1
KonstantinChe [14]
<h2>                     QUESTION # 1</h2>

Answer:

  • Total distance = 21 units (meters)
  • The average speed = 7 meter per second.

Step-by-step explanation:

To Determine:

If the whole run took the bug 3 seconds, what was its average speed?

Information Fetching and Solution Steps:

  • A beetle was running along a number line.
  • The beetle ran from 4 to 25.

Let suppose each unit on a number line represents 1 meter.

As the beetle ran from 4 to 25, so

the distance covered by beetle is:

                                           25 - 4 = 21 units. i.e. 21 meters

As the average speed can be determined by dividing the total distance by the total time, so

The average speed = total distance / total time

as

Total distance = 21 units (meters)

Total time = 3 seconds

so

The average speed = total distance / total time

                                 = 21/3

                                 = 7 meter per second

Therefore, the average speed = 7 meter per second.

                       

<h2>                       QUESTION # 2</h2>

Answer:

  • Total distance = 54 units (meters)
  • The average speed = 6 meter per second.

Step-by-step explanation:

To Determine:

If the whole run took the bug 9 seconds, what was its average speed?

Information Fetching and Solution Steps:

  • A beetle was running along a number line.
  • The beetle ran from 24 to 78.

Let suppose each unit on a number line represents 1 meter.

As the beetle ran from 24 to 78, so

the distance covered by beetle is:

                                         78 - 24 = 54 units. i.e. 54 meters

As the average speed can be determined by dividing the total distance by the total time, so

The average speed = total distance / total time

as

Total distance = 54 units (meters)

Total time = 9 seconds

so

The average speed = total distance / total time

                                 = 54/9

                                 = 6 meter per second

Therefore, the average speed = 6 meter per second.

6 0
3 years ago
In a collision, a 5 kg mass moving at 2m/s transfers all of its momentum to a 1 kg mass. What is the velocity of the 1kg mass af
statuscvo [17]
Answer:
velocity = 10 m/sec in the same direction as the first body did

Explanation:
The momentum of the body can be calculated as follows:
momentum = mass * velocity

For the first body, we have:
mass = 5 kg
velocity = 2 m/sec
momentum = mass * velocity
momentum = 5 * 2 = 10 kg.m/sec

We know that this momentum is transferred completely to the second body

For the second bode, we have:
momentum = 10 Kg.m/sec
mass = 1 kg
momentum = mass * velocity
10 = 1 * velocity 
velocity = 10/1
velocity = 10 m/sec

Finally, we should get the direction of the motion:
Both the velocity of the first and second bodies have positive values. Therefore, the second body is moving in the same direction as the first body did.

Hope this helps :)
6 0
2 years ago
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PLEASEEEE HELP!!!!! I WILL MAKE BRAINLEST!!!!!!!!!!!!<br> What's the common difference of 1,3,5,8
Llana [10]

Answer:

There is no common difference

Step-by-step explanation:

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I need to know the perimeter because i can't figure out some of the side lengths.
blsea [12.9K]
The primeter is the outside p=2+2 +3+1+1 so the primiter is 9
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