1+(-2-5)^2+(14-17)×4
1 answer:
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Hi again!
|2x - 3| - 1 > 4
|2x -3| > 4 + 1
|2x -3| > 5
Now let's solve the absolute value
We know either 2x -3 >5 or 2x -3<-5
Let's solve the first possibility
2x - 3 > 5
2x > 5+ 3
2x > 8
x > 8/2
x> 4
Now solve the second possibility
2x - 3 < -5
2x < -5 + 3
2x < -2
x < -2/2
x< -1
Thus the correct answer is x > 4 or x < -1
I used an online graphing calculator
I hope this helps again!
|2x - 3| - 1 > 4
|2x -3| > 4 + 1
|2x -3| > 5
Now let's solve the absolute value
We know either 2x -3 >5 or 2x -3<-5
Let's solve the first possibility
2x - 3 > 5
2x > 5+ 3
2x > 8
x > 8/2
x> 4
Now solve the second possibility
2x - 3 < -5
2x < -5 + 3
2x < -2
x < -2/2
x< -1
Thus the correct answer is x > 4 or x < -1
I used an online graphing calculator
I hope this helps again!