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3 years ago

1+(-2-5)^2+(14-17)×4

Mathematics

1 answer:

Maslowich3 years ago

6 0

Answer:

Step-by-step explanation:

1 + (-7)^2 + (-3)x4

1 + 49 + (-12)

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Solve for x ax+3b=2f

Paladinen [302]

You said ax + 3b = 2f

Subtract 3b from each side: ax = 2f - 3b

Divide each side by 'a' : x = (2f - 3b) / a

3 0

3 years ago

How can you represent a proportional relationship with an equation? PLS help me with an explanation.

earnstyle [38]

Answer:

A proportional relationship between a quantity y and a quantity x that has a constant of proportionality k is represented by the equation y = kx.

Step-by-step explanation:

hope this explains well, good luck !

8 0

2 years ago

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My Than purchased a bicycle costing RS 56oo from a dealer at 51 discount and a sold a profit of 10%. If he had soll it at sy dis

Alisiya [41]

Answer:

sp of bicycle =5600

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now,

profit(p)=sp-cp

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3 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

Find the missing lengths m and n in the rectangular prism.

Sav [38]

Answer:

where is the picture???

what are the given lengths?

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3 years ago