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oksano4ka [1.4K]
3 years ago
6

The life expectancy of a particular brand of tire is normally distributed with a mean of 40,000 and a standard deviation of 5,00

0 miles. What is the probability that a randomly selected tire will have a life of exactly 47,500 miles
Mathematics
1 answer:
timama [110]3 years ago
6 0

Answer: the probability that a randomly selected tire will have a life of exactly 47,500 miles is 0.067

Step-by-step explanation:

Since the life expectancy of a particular brand of tire is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = life expectancy of the brand of tire in miles.

µ = mean

σ = standard deviation

From the information given,

µ = 40000 miles

σ = 5000 miles

The probability that a randomly selected tire will have a life of exactly 47,500 miles

P(x = 47500)

For x = 47500,

z = (40000 - 47500)/5000 = - 1.5

Looking at the normal distribution table, the probability corresponding to the z score is 0.067

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grigory [225]

Answer:

a) $50,880

b) $48

c) 1060

Step-by-step explanation:

a)

-320x^2 + 1920x + 48000 = 0

This is a parabola that opens downward. It has a maximum value. The maximum value occurs at x = -b/(2a)

x = -b/(2a) = (-1920)/(2(-320)) = 1920/640 = 3

The maximum revenue, y, is the value of the function evaluated at x = 3.

f(x) = -320x^2 + 1920x + 48000

f(-3) = -320(3)^2 + 1920(3) + 48000

f(-3) = 50,880

The maximum revenue is $50,880

b)

Since maximum revenue occurs at x = 3, and since x represents the number of $4 discounts, the discount is 3 * $4 = $12. The price is $60 - $12 = $48

c)

$50,880/$48 = 1060

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3 years ago
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Lera25 [3.4K]

Answer:

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A salesperson had $240000 in sales last year,which is 60% is the sale she had this year Write an equation that finds the amount
Alenkinab [10]
A salesperson had 240,000 in sales last year.....which is 60% of the sales she had this year....
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