Answer:
Your annual expected value is -$550.
Step-by-step explanation:
0.002 probability that you will total your car.
If you total your car, you pay the insurance of $600, but you get the $25,000 insurance. So in total, the net value will be $24,400.
1-0.002 = 0.998 probability that you will not total your car.
In this case, you lose $600.
What is your annual expected value?
Multiply each net value by it's probability.
E = 0.002*24400 - 0.998*600 = -550
Your annual expected value is -$550.
The common denominator is 18
Answer:
27) x = 2^(y) – 5.
Asymptote: x = -5.
D: x > -5; (-5, infinity).
R: -infinity < f(x) < infinity; ARN;
(-infinity, infinity).
x → -infinity, f(x) → -infinity.
x → +infinity, f(x) → +infinity.
________________________
28) x = 2^-(y–3).
Asymptote: x = 0.
D: x > 0; (0, infinity).
R: -infinity < f(x) < infinity; ARN;
(-infinity, infinity).
x → -infinity, f(x) → +infinity.
x → +infinity, f(x) → -infinity.
________________________
29) x = 4^(y–2) + 1.
Asymptote: x = 1.
D: x > 1; (1, infinity).
R: -infinity < f(x) < infinity; ARN;
(-infinity, infinity).
x → -infinity, f(x) → -infinity.
x → +infinity, f(x) → +infinity.
________________________
1. (3,-2)
2. (-5,-4)
3. (-20,11)
4. (2,3)
5. (13/7, 40/7)
the phrase which i believe is correct is A. 7 more than 2 times m