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bixtya [17]
2 years ago
12

PLEASE HELP! 50 POINTS!!!!! Which expression(s) are equivalent to -2x + 10

Mathematics
1 answer:
galina1969 [7]2 years ago
7 0
The answer is b hope that helps
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The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of app
AfilCa [17]

Answer:

Q(t) = 4.5(1.013)^{t}

The world population at the beginning of 2019 will be of 7.45 billion people.

Step-by-step explanation:

The world population can be modeled by the following equation.

Q(t) = Q(0)(1+r)^{t}

In which Q(t) is the population in t years after 1980, in billions, Q(0) is the initial population and r is the growth rate.

The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of approximately 1.3%/year.

This means that Q(0) = 4.5, r = 0.013

So

Q(t) = Q(0)(1+r)^{t}

Q(t) = 4.5(1.013)^{t}

What will the world population be at the beginning of 2019 ?

2019 - 1980 = 39. So this is Q(39).

Q(t) = 4.5(1.013)^{t}

Q(39) = 4.5(1.013)^{39} = 7.45

The world population at the beginning of 2019 will be of 7.45 billion people.

6 0
3 years ago
HELPPPP I WILL GIVE BRAINLYIST
Furkat [3]
Give me the characteristics and I’ll give you the examples
7 0
3 years ago
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What fraction of 60 is 18
nordsb [41]
10/3 

hope this helped
3 0
3 years ago
X-4y=28 2x+y=2 Elimination
makvit [3.9K]

\left\{\begin{array}{ccc}x-4y=28\\2x+y=2&\text{multiply both sides by 4}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}x-4y=28\\8x+4y=8\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad9x=36\qquad\text{divide both sides by 9}\\.\qquad\boxed{x=4}\\\\\text{Put the value of x to the second equation:}\\\\2(4)+y=2\\8+y=2\qquad\text{subtract 8 from both sides}\\\boxed{y=-6}\\\\Answer:\ \boxed{x=4\ and\ y=-6\to(4,\ -6)}

3 0
3 years ago
The sales decay for a product is given by S = 70000e^ -0.8x where S is the monthly sales and x is the number of months that have
Gre4nikov [31]

Answer:

After 5.31 months sales will drop below 1000 and 5 months after the end of the campaign sales will be 1282.09

Step-by-step explanation:

Let's find the solutions for the two questions.

First question: How many months after the end of the campaign will sales drop below 1000.

Because the problem asks for how many months, and since 'x' represents month variable, then the problem is asking for 'x'.

Using the same equation for sales we can observe the following:

S=70000*e^{-0.8X}, but we have S which is 1000, so:

1000=70000*e^{-0.8X} which is equal to:

1000/70000=e^{-0.8X} which is equal to:

1/70=e^{-0.8X} by applying ln(x) properties:

ln(1/70)=ln(e^{-0.8X}) which is equal to:

ln(1/70)=-0.8X which is equal to:

ln(1/70)/(-0.8)=X so:

X=5.31 months

Second question: what will be the sales 5 months after the end of the campaign.

Because the problem asks for what will be the sales, and since 'S' represents the sales, then the problem is asking for 'S'.

Using the same equation for sales we can observe the following:

S=70000*e^{-0.8X}, but we have x which is 5 months, so:

S=70000*e^{-0.8*5} which is equal to

S=1282.09

In conclusion, after 5.31 months sales will drop below 1000 and 5 months after the end of the campaign sales will be 1282.09.

8 0
3 years ago
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