For the right triangles below, find the exact values of the side lengths b and d.
1 answer:
Answer:
Step-by-step explanation:
The question lacks the required diagram. Find the diagram attached below;
According to the first triangle, taking 30° as the reference angle, the opposite side of the triangle will be 5 and the adjacent will be the unknown side "b"
According to SOH, CAH, TOA;
tanθ = opposite/adjacent (using TOA)
Given;
θ = 30°, opposite = 5 and adjacent = b
tan30° = 5/b
b = 5/tan30°
b = 5/(1/√3)
b = 5*√3/1
b = 5√3
According to the 45° triangle, the opposite side of the triangle will be d and the hypotenuse will be 7
Using SOH;
sinθ = opposite/hypotenuse
Given;
θ = 45°, opposite = d and adjacent = 7
sin45° = d/7
d = 7sin45°
d = 7(1/√2)
d = 7/√2
Rationalize 7/√2
= 7/√2*√2/√2
=7√2/2
Hence the value of d is 7√2/2
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Answer:
We can only be certain that <em>a</em> weighs 12.
There are infinitely many possiblities for <em>b</em> and <em>c</em>.
Step-by-step explanation:
We have the equation:
Each variable indicates a weight.
We would like to determine the weights of each variable (if possible).
First, we can rearrange the equation to acquire:
We can combine like terms:
Notice that both sides have 2<em>b</em> and 3<em>c</em>. Therefore, it is possible for us to cancel them since each nullify the other side. So, we will subtract 2<em>b</em> and 3<em>c</em> from both sides. This yields:
Therefore, we can solve for <em>a</em>. Subtract 2<em>a</em> from both sides:
Hence, the weight of <em>a</em> is 12.
Using the newly acquired information, we can go back to our simplified equation:
Since <em>a</em> is 12:
Evaluate:
Simplify:
We can subtract 36 from both sides:
As you can see, this is a true statement.
Since this is a true statement, there are infinitely many possible values for <em>b</em> and <em>c</em>.
Therefore, the only weight we are <em>certain</em> of knowing is weight <em>a</em> weighing 12.