X^2 + y^2 - 2x + 8y - 47 = 0
x^2 + y^2 - 2x + 8y = 47
(x^2 - 2x) + (y^2 + 8y) = 47
(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47
(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2
(x - 1)^2 + (y + 4)^2 = 64 = 8^2
r=8
To test if this is a right triangle, let's test these side lengths with the Pythagorean Theorem.
a^2 + b^2 = c^2
c is the hypotenuse, the longest side of a right triangle.
a and b are the legs of the right triangle.
a = 7
b = 15
c = 17
7^2 + 15^2 = 17^2 ?
49 + 225 = 289 ?
274 ≠ 289
Thus, this triangle is not a right triangle since it does not satisfy the Pythagorean Theorem.
Have an awesome day! :)
She received 15% off, so she actually paid 85%
0.85(( 3*4.95) + (2* 3.25) + (2*1.75) + 5.35)) = 0.85(30.20) = 25.67
um...I have double checked this, and I am not getting an answer choice.
Answer:
see the explanation
Step-by-step explanation:
we know that
The area of the base of a cylinder is given by the formula
where
r is the radius of the circular base
If the radius is doubled
then
The new base area is
so
therefore
The new area of the base is 4 times the area of the original base
