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Inga [223]
3 years ago
9

Click on the graph below to create a quadrilateral with vertices at the following points. (-4,9), (-8,9), (-9,7), (-9, 4)​

Mathematics
1 answer:
Shalnov [3]3 years ago
4 0

Given (-4,9) (-8,9),(-9,7,(-9,4)

...

To Find : plot the point and draw quadrilateral

Solution:

(-4,9)

go 4 left of origin and then go 9 up

(-8,9)

go 8 left of origin and then go 8 up

(-9,7)

go 9 left of origin and then go 7 up

(-9,4)

go 9 left of origin and then go join (-4,9) with (-8,9) and (-9,4) 4 up

join (-9,7) with (-8,9) and (-9,4)

Quadrilateral is constructed

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{ \boxed{\boxed{\begin{array}{cc} \maltese  \bf \: given \\  \\  \rm \: f(x) = ( {x}^{2}  + 16)( {x}^{2} - 9) \\  \\  \bf \: for \: zeroes \\  \\ \pink{ \boxed{\boxed{\begin{array}{c | c}   \bf \:  {x}^{2} + 16 = 0 & \bf \: {x}^{2}  - 9 = 0 \\  \\  =  >  {x}^{2}  =  - 16& {x}^{2}  = 9 \\  \\  =  > x =  \pm \sqrt{ - 16} &x =  \pm \:  \sqrt{9}  \\  \\  =  > x =  \pm \sqrt{ {i}^{2}  {4}^{2} } &x =  \pm \:  \sqrt{ {3}^{2} } \\  \\  =  > x =  \pm \: 4i&x =  \pm3  \end{array}}}}   \\  \\  \rm \: x =  \pm3 \: and \pm \: 4i\end{array}}}}

Option A is the correct answer

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