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mr Goodwill [35]
3 years ago
12

Can u help me on this

Mathematics
2 answers:
Assoli18 [71]3 years ago
8 0

Answer:

Step-by-step explanation:

-3x - 6 = 18

The first step should be to add 6 to both sides.

- 3x = 24

The second step should be dividing each side by - 3x

X = - 8

NeTakaya3 years ago
5 0

Answer: The First Step is -3x=24 and the Second Step is x=-8

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Could someone please help me urgently ty!​
Ede4ka [16]

Answer:

m<PRQ=15°

Step-by-step explanation:

so we're given that PQ and RQ are sides of a regular 12-sided polygon (dodecagon)

a regular polygon is a polygon that has all angles be the same measure AND have all sides be the same length

because of that, PQ=RQ, and ΔPQR is isoceles

now we need to find what the question is asking for: m<PRQ

because of base-angles theorem, m<PRQ=m<RPQ

we need to find m<PQR

a dodecagon is 1800° in measure

and we need 1/12th of that measure, since <PQR is 1 out of the 12 interior angles on the dodecagon (a dodecagon has 12 vertecies, so 12 angles). Also because the polygon is regular, every interior angle has the same measure.

so find the measure of <PQR

<PQR= 1/12*1800=150°

now to find the measure of <PRQ:

there are 180° in a triangle

so subtract 150° from 180°

180°-150°=30°

30° is the sum of the base angles (<PRQ is one of the base angles in a triangle)

the base angles are the same measure, so that means the measure of <PRQ is 1/2 the measure of the sum of the base angles

therefore m<PRQ=15°

hope this helps!

7 0
3 years ago
HELP ILL GIVE BRAINLIEST what’s the surface area and the volume?
MariettaO [177]

Answer:

i dont know im so sorry for making you feel like you

Step-by-step explanation:

dont know im so sorry for making you feel like you

3 0
3 years ago
Find the area of the figure below, formed from a triangle and a parallelogram.
madreJ [45]

Hope it helps

pls mark me as Brainliest

7 0
3 years ago
Rationalize <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%20%5Csqrt%7B7%7D%20%2B%203%20%5Csqrt%7B3%7D%20%20%7D%20"
Ivahew [28]
\dfrac{1}{2 \sqrt{7} + 3 \sqrt{3}  }

= \dfrac{1}{2 \sqrt{7} + 3 \sqrt{3} } \times  \dfrac{2 \sqrt{7} - 3 \sqrt{3}}{2 \sqrt{7} - 3 \sqrt{3}}

=\dfrac{2 \sqrt{7} - 3 \sqrt{3}}{(2\sqrt{7})^2 - (3\sqrt{3})^2}

=\dfrac{2 \sqrt{7} - 3 \sqrt{3}}{28 - 27}

=\dfrac{2 \sqrt{7} - 3 \sqrt{3}}{1}

=2 \sqrt{7} - 3 \sqrt{3}

6 0
3 years ago
Plz help me on number 4
jekas [21]

9514 1404 393

Answer:

  6 : 5

Step-by-step explanation:

The diagram shows you that the boxes have a length (L) to width (W) ratio such that ...

  3L = <em>l</em> = 4W

  L/W = 4/3

Suppose we call the width of the box 3 units, then its length is 4 units, and we have the crate dimensions ...

  <em>l</em> = 4(3) = 3(4) = 12

  <em>w</em> = 3+3+4 = 10

Then the ratio <em>l </em>: <em>w</em> is 12 : 10 = 6 : 5.

8 0
3 years ago
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