Bases release OH- ions in solutions, whereas Acids release H+ ions in solutions
The question is incomplete and the complete question is
Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.
Answer:
AABb or AaBB
Explanation:
We know that,
aabb genotype - 6 cm
AABB genotype- 16-cm
To calculate the length of earlobe contributed by each allele in a genotype is :
1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)
2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)
Now to have the earlobe to be 13.5 cm long then the genotype must be
13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B
Therefore, the genotype will be-either AABb or AaBB
<span>Infections
</span><span>viruses
</span>Bacteria
Mold
and so on.
sun, salmon, maple trees, bears, plankton, whales, grass, cows, humans, shrimp, caterpillars, finches (small birds), hawks
Iteru [2.4K]
Yes, they are all living things that exist in our world.
Answer:
The correct answer is- C. double or single-stranded DNA or double or single-stranded RNA.
Explanation:
All the viruses are intracellular parasites which means they obtain their nutrition from their host. Viruses do not have cellular level of organization. They only have their nucleic acid which is surrounded by a protein coat called a capsid.
The nucleic acid in viruses can be of different types. It can be single or double-stranded DNA or single or double-stranded RNA. Their genome can be linear or circular. They inject their genetic material in their host and introduce it in the host genome. Therefore the correct answer is C.
