To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
First lets simplify the first term and yield (2a)
The second term:
1. 2a * (-1/2) = -a
2. -a + a = 0
Now we have simplified both terms to: (2a) (0)
Anything multiplied by 0 is 0, so the answer is also 0.
Answer:
(5, 15)
Step-by-step explanation:
-x + 6x = 5
5x = 5
x = 5
y = 3 (5)
y = 15
You can substitute 6x for 2y because it says y = 3x. So 2y is gonna be 6x because you have to multiply it by 2 since it's 2y not just y.
Answer:
.45 times 6= 2.7
29 times 8 =232
.62 times 19 = 11.78
8.7 times 12=104.4
11.9 times 4 = 47.6
Step-by-step explanation:
Answer:
Add x x and 0 0 . Since g(f(x))=x g ( f ( x ) ) = x , f−1(x)=x+7 f - 1 ( x ) = x + 7 is the inverse of f(x)=x−7 f ( x ) = x - 7
Step-by-step explanation:
