Answer:
12 m
Step-by-step explanation:
The path of a football has been modeled by the equation:
where h represents the height and d represents the horizontal distance.
When the ball lands, it means that its height is back at 0 metres. This means that we have to find horizontal distance, d, when height, h, is 0.
=> 
∴ d = 0 m
and
10d - 120 = 0
=> d = 120 / 10 = 12 m
There are two solutions for d when h = 0 m.
The first solution (d = 0 m) is a case where the ball has not been thrown at all. This means the ball has not moved away from the football player and it is still on the ground.
The second solution is the answer to our problem (d = 12 m). The ball lands at a horizontal distance of 12 m
Answer:
The one on the left answer the 1st and the one on the right answers the 2nd
Step-by-step explanation:
Answer:
B: The elevation of the chameleon
Step-by-step explanation:
The Fly is <em><u>above</u></em> the chameleon, so its elevation should be represented by a "positive number"(Example of positive number: 16)
Also,
The Grasshopper is <em><u>below </u></em>the chameleon, so its elevation should be represented by a "negative number"(Example of negative number: -23)
ඞHope this helps u because i got dis question from Khan Academyඞ
Answer:
13.41 cm
Step-by-step explanation:
The radius, height, and HALF of vertical angle makes a triangle.
Where
Radius will be the base of the triangle
Height will be the "height" of the triangle
Top angle will be HALF of vertical angle (40/2 = 20)
From the 20 degree angle, the side "opposite" would be the radius, which is 30. The side "adjacent" would be the height, let it be h.
<em>Which trig ratio relates opposite and adjacent? Yes, that is TAN. Thus we can write:</em>
Tan(20) = opposite/adjacent
Tan(20) = 30/h
h = 30/Tan(20)
h = 13.41
So
The height of the cone would be around 13.41 cm
Problem 1
Answer: Independent
The reason why is because each bag is separate from one another, so one event doesn't affect the other. If we know the result of what we pulled out of one bag, it doesn't change the probability of the other event.
======================================
Problem 2
Answer: Dependent
Assuming you do not put the first card back, then the probability of picking a King on the second draw will be different than if you picked a King on the first draw. With all 52 cards in the deck, the probability of getting a king is 4/52 = 1/13. It changes to 4/51 after we picked out an ace for the first card (and didn't put that first card back).
