x² - 14x + 46 = 0
subtract 46 from both-side
x² - 14x = -46
Add the square of the half of the co-efficient of x
x² - 14x + (-7)² = -46 + 7²
(x-7)² = -46 + 49
(x-7)² =3
Take the square root of both-side
x-7 = ±√3
x-7= ±1.732
Add 7 to both-side of the equation.
x= 7 ± 1.732
Eithe x= 7 + 1.732 or x= 7 - 1.732
x=8.732 or x=5.268
Therefore x = 8.732 , 5.268
Answer:
B) 72
Step-by-step explanation:
The n-th term of an arithmetic sequence An = a1 + (n - 1) d
Given :
a28 = 423/4 and d = 5/4
So
a28 = a1 + (28 - 1)5/4
Now plug in a28 = 423/4
423/4 = a1 + 27(5/4)
a1 = 423/4 - 27(5/4)
= 423/4 - 135/4
a1 = (423-135)/4
a1 = 288/4
a1 = 72
Thank you.
I'm assuming this is trig - is this all for one triangle and is it right?
So we have v(w) = 2w - 1
Now we make the following change: w ---> w +3.
So we change every "w" into a "w+3" as follows:
v(w) = 2w - 1 --------> v(w+3) = 2*(w+3) - 1
Let's solve this.
2*(w+3) - 1
2*w + 2*3 - 1
2w + 6 - 1
2w + 5
So
v(w+3) = 2w + 5