Answer:
By the Pythagoras theorem, the hypotenuse (c), is equivalent to:
a^2+ b^2= c^2 where a and b are the other two sides of the right angled triangle, hence c= square root (15^2+ 20^2)= 25
I assume you mean one that is not rational, such as √2. In such a case, you make a reasonable estimate of it's position, and then label the point that you plot.
For example, you know that √2 is greater than 1 and less than 2, so put the point at about 1½ (actual value is about 1.4142).
For √3, you know the answer is still less than 4, but greater than √2. If both of those points are required to be plotted just make sure you put it in proper relation, otherwise about 1¾ is plenty good (actual value is about 1.7321).
If you are going to get into larger numbers, it's not a bad idea to just learn a few roots. Certainly 2, 3, and 5 (2.2361) and 10 (3.1623) shouldn't be too hard.
Then for a number like 20, which you can quickly workout is √4•√5 or 2√5, you could easily guess about 4½ (4.4721).
They're usually not really interested in your graphing skills on this sort of exercise. They just want you to demonstrate that you have a grasp of the magnitude of irrational numbers.
<span>54*8+6+14
Multiply 54 by 8
432 + 6 + 14
Add 6 to 432
438+14
Add
Final Answer: 452
</span>
Solve for y like the top equation:
2y = -4ax + 11
2y/2 = -4ax/2 + 11/2
y = -2ax + 11/2
