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zhenek [66]
3 years ago
8

Please take a look at the imageeeeeeeeeeeee

Mathematics
1 answer:
kramer3 years ago
3 0

Answer:

I'm not alone

It's just me and your ghost

And this cripplin' depression

I thought I learned my lesson

But I threw out my phone

And I burned all your clothes

And now I'm not alone

It's just me and your ghost

[Verse 1]

I got four red bottoms up in flames at my place now (Place now)

I burned three Chanel dresses, three words we don't say now (Say now)

And it's hard not to drink when it's the one thing I think about

It's a lot of spiders in the attic, I don't mean to be dramatic

But I think it's kinda tragic who we magically became now

[Chorus]

I'm not alone

It's just me and your ghost

And this cripplin' depression

I thought I learned my lesson

But I threw out my phone

And I burned all your clothes

And now I'm not alone

It's just me and your ghost

[Post-Chorus]

Me and your ghost

Me and your ghost

Me and your ghost

Me and your ghost (Yeah)

[Verse 2]

Tell me what I'm s'posed to do with all these pictures on my iPhone

Even all them videos only you and I know

You never cared about me, you just care about the likes though

Every time you pop up, you should see my stupid eye roll

I can't even kick it with the homies that we both know

I can't even vist with any places that we used to go

Now all I got is just the memories of us though

Burn it all down to the ground with your ghost

[Chorus]

I'm not alone

It's just me and your ghost

And this cripplin' depression

I thought I learned my lesson

But I threw out my phone

And I burned all your clothes

And now I'm not alone

It's just me and your ghost

[Post-Chorus]

Me and your ghost

Me and your ghost

Me and your ghost

Me and your ghost

[Bridge]

I wish I could take back summer nights

Erase all the vibes

Leave the memories out to dry

Delete forever, no archive

Take the words you said to me

Hold on to them intentionally

I know that eventually

I'ma set fire to the one thing I love the most

Burn it all to the ground with your ghost

[Chorus]

I'm not alone

It's just me and your ghost

And this cripplin' depression

I thought I learned my lesson

But I threw out my phone

And I burned all your clothes

And now I'm not alone

It's just me and your ghost

[Post-Chorus]

Me and your ghost

Me and your ghost

Me and your ghost

Me and your ghost

Step-by-step explanation:

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Not sure if any of this is correct, but it’s what I got so far
Irina18 [472]

Problem 1 is correct. You use the pythagorean theorem to find the hypotenuse.

==================================================

Problem 2 has the correct answer, but one part of the steps is a bit strange. I agree with the 132 ft/sec portion; however, I'm not sure why you wrote \frac{1 \text{ sec}}{132 \text{ ft}}=\frac{0.59\overline{09}}{78 \text{ ft}}*127 \text{ ft}

I would write it as \frac{1\text{ sec}}{132 \text{ ft}}*127 \text{ ft} = \frac{127}{132} \text{ sec} \approx 0.96 \text{ sec}

==================================================

For problem 3, we first need to convert the runner's speed from mph to feet per second.

17.5 \text{ mph} = \frac{17.5 \text{ mi}}{1 \text{ hr}}*\frac{1 \text{ hr}}{60 \text{ min}}*\frac{1 \text{ min}}{60 \text{ sec}}*\frac{5280 \text{ ft}}{1 \text{ mi}} \approx 25.667 \text{ ft per sec}

Since the runner needs to travel 90-12 = 78 ft, this means\text{time} = \frac{\text{distance}}{\text{speed}} \approx \frac{78 \text{ ft}}{25.667 \text{ ft per sec}} \approx 3.039 \text{ sec}

So the runner needs about 3.039 seconds. In problem 2, you calculated that it takes about 0.96 seconds for the ball to go from home to second base. The runner will not beat the throw. The ball gets where it needs to go well before the runner arrives there too.

-------------

The question is now: how much of a lead does the runner need in order to beat the throw?

Well the runner needs to get to second base in under 0.96 seconds.

Let's calculate the distance based on that, and based on the speed we calculated earlier above.

\text{distance} = \text{rate}*\text{time} \approx (25.667 \text{ ft per sec})*(0.96 \text{ sec}) \approx 24.64032 \text{ ft}

This is the distance the runner can travel if the runner only has 0.96 seconds. So the lead needed is 90-24.64032 = 65.35968 feet

This is probably not reasonable considering it's well over halfway (because 65.35968/90 = 0.726 = 72.6%). If the runner is leading over halfway, then the runner is probably already in the running motion and not being stationary.

As you can see, the runner is very unlikely to steal second base. Though of course such events do happen in real life. What may explain this is the reaction time of the catcher may add on just enough time for the runner to steal second base. For this problem however, we aren't considering the reaction time. Also, not all catchers can throw the ball at 90 mph which is quite fast. According to quick research, the MLB says the average catcher speed is about 81.8 mph. This slower throwing speed may account for why stealing second base isn't literally impossible, although it's still fairly difficult.

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