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Mrrafil [7]
3 years ago
13

What is the difference between rigid and nonrigid transformations?

Mathematics
1 answer:
never [62]3 years ago
6 0

Answer:

The rigid transformation, which does not change the shape or size of the preimage. The non-rigid transformation, which will change the size but not the shape of the preimage.

Step-by-step explanation:

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Step-by-step explanation:

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Identify the missing side length using a scale factor of 1.5
FromTheMoon [43]
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5 0
3 years ago
Can anyone answer me this question ​
yuradex [85]

Question 1:

For this case we have the following functions:

f (x) = 4x + 1\\g (x) = x ^ 3 + 1

We must findg_ {o} f (0):

By definition we have to:

g_ {o} f = g (f (x))\\f_ {o} g = f (g (x))

g (f (x)) = (4x + 1) ^ 3 + 1

We substitute x = 0:

g (f (0)) = (4 (0) +1) ^ 3 + 1 = 1 ^ 3 + 1 = 2

So, we have that g (f (0)) = 2

Answer:

g (f (0)) = 2

Question 2:

For this case we have the following functions:

f (x) = 4x + 1\\g (x) = x ^ 3 + 1

We must find f_ {o} g (0):

By definition we have to:

f_ {o} g = f (g (x))\\f (g (x)) = 4 (x ^ 3 + 1) + 1 = 4x ^ 3 + 4 + 1 = 4x ^ 3 + 5

We substitute x = 0:

f (g (0)) = 4 (0) ^ 3 + 5 = 5

Answer:

f (g (0)) = 5

Question 3:

For this case we must find the inverse of the following function:

h (x) = \frac {2x + 1} {3}

To do this, we follow the steps below:

We change y for h (x):

y = \frac {2x + 1} {3}

We exchange variables:

x = \frac {2y + 1} {3}

We clear the value of the variable "y":

3x = 2y + 1\\3x-1 = 2y\\y = \frac {3x} {2} - \frac {1} {2}

We change y for h^{ -1} (x):

h ^{ - 1} (x) = \frac {3x} {2} - \frac {1} {2}

Answer:

h ^ {- 1} (x) = \frac {3x} {2} - \frac {1} {2}

3 0
4 years ago
OK I need help I ever tried several ways .
zhenek [66]

ok so u need to find the gcd and then subtract.

7 0
3 years ago
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