Question

Write (2x+1)(3x-8) in expanded form

Answer 1

$(2x + 1)(3x - 8) \\ 6x {}^{2} - 16x + 3x - 8 \\ 6x {}^{2} - 13x - 8$

Answer 2

(2x+1)(3x-8)

To write it in expanded form we use FOIL method

FOIL ----> First Outer Inner Last

First = 2x * 3x = $6x^2$

Outer = 2x * -8 = -16x

Inner = 1 * 3x = 3x

Last = 1 * -8 = -8

Now write all the terms in order

$6x^2 - 16x + 3x -8$

Combine like terms

$6x^2 - 13x -8$