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kenny6666 [7]
3 years ago
9

Help!!!!! please!!!!!

Mathematics
1 answer:
wlad13 [49]3 years ago
8 0

Answer:

50

Step-by-step explanation:

10(10)/2

100/2

50

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Solve the system of linear equations using the
MArishka [77]

Answer:

no solution

Step-by-step explanation:

y = -2x + 3

6x + 3y = -3

the substitution method means you plug one equation into the next, because the first equation gives us a solution for y we can go ahead and plug that into y of the second equation

6x + 3(-2x + 3) = -3

6x - 6x + 9 = -3

9 = -3

which is false meaning that there are no solutions and the lines don't touch at any point

8 0
3 years ago
0647grams nearest tenth
balu736 [363]
1000 is the answer! hoped I helped
8 0
4 years ago
What is the simplified of this ?
Hatshy [7]

Answer:

The correct answer is A) x^6y^8

Step-by-step explanation:

The easiest way to find this is to first square the second term.

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Now we multiply that by the first parenthesis.

(x^2y^2)(x^4y^6) = x^6y^8

4 0
3 years ago
In the sequence {1, 5, 9, 13, 17, …}, which term is a3?<br> a3 = 17<br> a3 = 9<br> a3 = 1<br> a3 = 5
kozerog [31]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the Answer ~

\qquad \sf  \dashrightarrow \: a_3 = 9

The term \sf a_3 is equal to third term, that is 9

3 0
3 years ago
Calculate how much more money does $1000 earn in 8 years compounded daily at 3%,
STatiana [176]

Answer:

To determine the compound interest of a certain investment, the following formula should be used:

X = Initial value (1 + interest rate / number of compositions) ^ years x number of compositions

Thus, in the assumption of an investment of $ 1,000 with interest compounded daily at 3% for 8 years, the formula would be the following:

X = 1,000 x (1 + 3/365) ^ (8x365)

X = 1,271.24

On the other hand, in the case of an investment of $ 1,000 with compound interest every 6 months at 3% for 8 years, the formula would apply as follows:

X = 1,000 x (1 + 3/2) ^ (8x2)

X = 1,268.99

6 0
3 years ago
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