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Aliun [14]
3 years ago
13

Please answer both questions!! Will mark brainliest!!

Mathematics
1 answer:
musickatia [10]3 years ago
5 0

Answer:

#1- is C /  #2- is b

Step-by-step explanation:

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The number of small lawns Isabella can rake depends on the amount of time she spends raking. Isabella can rake 3 lawns in 3.75 h
ycow [4]

Answer:

1) 4      2)7

Step-by-step explanation:

1) If we divide 3.75/3=1.25 which is the amount of time she takes per yard so if we add another yard to what she has already done we find she only could do one more yard in 5 hours 3.75+1.25=5.00 So she can only rake 4 yards in 5 hours

2) If we divide 20.25/3=6.75 we find that each ticket is $6.75 so we must divide that by 47.25 to get the amount of tickets 47.25/6.75=7


6 0
3 years ago
What is the name of the period that has 913 in the number 913,256
Lana71 [14]
thousands period is the answer
4 0
4 years ago
The answer to c plz
NikAS [45]

Answer:

≈ 30.63 cm²

Step-by-step explanation:

The shaded area is calculated by subtracting the area of the inner circle from the area of the outer circle.

outer circle has radius = 8 ÷ 2 = 4 and inner circle has radius = 5 ÷ 2 = 2.5

shaded area = πr₁² - πr₂² (r₁ is outer and r₂ is inner )

A = π (4² - 2.5²)

   = π(16 - 6.25) = 9.75π ≈ 30.63 cm²

           

5 0
3 years ago
Use Green's Theorem to calculate the circulation of F =2xyi around the rectangle 0≤x≤8, 0≤y≤3, oriented counterclockwise.
Tamiku [17]

Green's theorem says the circulation of \vec F along the rectangle's border C is equal to the integral of the curl of \vec F over the rectangle's interior D.

Given \vec F(x,y)=2xy\,\vec\imath, its curl is the determinant

\det\begin{bmatrix}\frac\partial{\partial x}&\frac\partial{\partial y}\\2xy&0\end{bmatrix}=\dfrac{\partial(0)}{\partial x}-\dfrac{\partial(2xy)}{\partial y}=-2x

So we have

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_D-2x\,\mathrm dx\,\mathrm dy=-2\int_0^3\int_0^8x\,\mathrm dx\,\mathrm dy=\boxed{-192}

6 0
3 years ago
Please answer this question
stira [4]

Graph 1: Domain = 2 <= x < 12  

Graph 1: Range = {2,4}

Graph 2: Domain = 3 <= x <= 10  

Graph 2: Range = -6 <= y <= 4

Graph 3: Domain = 4 < x < 11  

Graph 4: Range = -6 <= y < 2

3 0
3 years ago
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