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ivanzaharov [21]

4 years ago

7

Monisha and Dave each sold more magazine subscriptions as part of a fundraiser Monisha rays have as much money as the rays toget

her the race $213.75 what is the total amount of money the money she has raised

1 answer:

tatyana61 [14]4 years ago

4 0

Monisha = x/2

Dave = x

x + (x/2) = 213.75

1. Solve for x.

2. Evaluate x/2 to find the total amount raised by Monisha.

Take it from here.

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Can anyone help? i suck at math lol

aleksley [76]

Answer:16384

Step-by-step explanation:

4*4*4*4+4*4*4

6 0

3 years ago

A study1 conducted in July 2015 examines smartphone ownership by US adults. A random sample of 2001 people were surveyed, and th

dusya [7]

Answer:

a) Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

b) $z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{688+671}{989+1012}=0.679$

c) $z=\frac{0.696-0.663}{\sqrt{0.679(1-0.679)(\frac{1}{989}+\frac{1}{1012})}}=1.58$

d) For this case we see that $\hat p_1 > \hat p_2$ so then the answer for this cae would men

Step-by-step explanation:

Information given

$X_{1}=688$ represent the number of men with smartphone

$X_{2}=671$ represent the number of women with smartphone

$n_{1}=989$ sample of men selected

$n_{2}=1012$ sample of women selected

$p_{1}=\frac{688}{989}=0.696$ represent the proportion of men with smartphone

$p_{2}=\frac{671}{1012}=0.663$ represent the proportion of women with smartphone

$\hat p$ represent the pooled estimate of p

z would represent the statistic

$p_v$ represent the value

Part a

We want to test if we have difference in the proportion owning a smartphone between men and women, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

Part b

The statistic for this case is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{688+671}{989+1012}=0.679$

Part c

Replacing the info given we got:

$z=\frac{0.696-0.663}{\sqrt{0.679(1-0.679)(\frac{1}{989}+\frac{1}{1012})}}=1.58$

Part d

For this case we see that $\hat p_1 > \hat p_2$ so then the answer for this cae would men

4 0

3 years ago

If you have 26 ounces of chicken how many people can you feed

IRISSAK [1]

Answer:

between 8 and 9

Step-by-step explanation:

the normal serving size for meat is around 3 ounces so 26 divided by 3 would be between 8 and 9

6 0

3 years ago

Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They

ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

$P = 2$

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Required

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If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

This gives:

$P(G_1\ and\ G_2) = P(G_1) * P(G_2)$

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$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}$

$P(G_1\ and\ G_2) = \frac{3}{10}$

$P(P_1\ and\ P_2) = P(P_1) * P(P_2)$

$P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}$

$P(P_1\ and\ P_2) = \frac{1}{10}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

$P(Same) = \frac{3}{10} + \frac{1}{10}$

$P(Same) = \frac{3+1}{10}$

$P(Same) = \frac{4}{10}$

$P(Same) = \frac{2}{5}$

8 0

3 years ago

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Answer:

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125.69 Would be Greater.

Step-by-step explanation:

First number to the right of the decimal is the tenths place 2nd number would be hundredths and you'd increase etc.

8 0

3 years ago