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lara [203]
3 years ago
5

A letter is randomly chosen from the word candlestick.find the probability

Mathematics
2 answers:
Solnce55 [7]3 years ago
8 0
P(v)=3/11

p(nors)=1/11+1/11=2/11

p(!c)=10/11
Marianna [84]3 years ago
3 0

Answer:

P (a vowel) =3/11

P (n or s) =2/11

P (not c )=9/11

Step-by-step explanation:

A letter is randomly chosen from the word candlestick

P(vowel)=number of vowels/total number of letters

             =3/11

P(n or s)= number of letters which are n or s/total number of letters

             = 2/11

P(not c)=number of letters except c/total number of letters

            = 9/11

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Step-by-step explanation:

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3 years ago
Which ratio is equivalent to five nine
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3 0
2 years ago
The demand for a daily newspaper at a newsstand at a busy intersection is known to be normally distributed with a mean of 150 an
AURORKA [14]

Answer:

171 newspapers.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 150, \sigma = 25

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Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - 150}{25}

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4 0
3 years ago
How to cross multiply 9/12 =x/100?
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