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Phantasy [73]
3 years ago
9

A line has a slope of-1 and passes through the point (1, -8) .What is its equation in slope -intercept form?

Mathematics
1 answer:
Nostrana [21]3 years ago
6 0
M = -1

Passes through (1, -8)

Slope intercept form : y = mx+b

Where m = slope, and b = y-intercept.

-8 = y-intercept

Simply plug in the values for the slope and y-intercept into the slope-intercept form.

y = mx + b

y = -x - 8

~Hope I helped!~



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3 years ago
What is the slope of the line passing through the points (1, 2) and (5, 4)?​
bulgar [2K]
<h2>SOLVING</h2>

\Large\maltese\underline{\textsf{A. What is Asked}}

What is the slope of the line passing through the point (1,2) and (5,4)

\Large\maltese\underline{\textsf{This problem has been solved!}}

Formula used, here  \bf{\dfrac{y2-y1}{x2-x1}

_______________________________________________________

\bf{\dfrac{4-2}{5-1} | simplify

\bf{\dfrac{2}{4} | reduce

\bf{\dfrac{1}{2}

\rule{300}{1.7}

\bf{Result:}

         \bf{=Slope:\dfrac{1}{2}

\boxed{\bf{aesthetic\not101}}

3 0
1 year ago
Read 2 more answers
Lim x-1 x2 - 1/ sin(x-2)
balu736 [363]

Answer:

           \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0

Explanation:

Assuming the correct expression is to find the following limit:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}

Use the property the limit of the quotient is the quotient of the limits:

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Evaluate the numerator:

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Evaluate the denominator:

  • Since         \lim_{x \to1}sin(x-2)\neq 0

                  \frac{0}{\lim_{x \to1}sin(x-2)}=0

4 0
2 years ago
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