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3 years ago

The sum of two consecutive odd integers is 244244. Find the two integers.

1 answer:

7 0

Let one of the integers be x

Other integer = x + 2

x + x +2 = 244244
2x = 244242
x = 122121

x + 2 = 122123

Thus the two integers are 122121 and 122123

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What are some key ways to solve math word problems? How can you tell which math category does a problem solving question fall in

OlgaM077 [116]

Look for "Math Clues." Math Clues are like how many, fewer, left, and more.

How many is the total.

Fewer & Left are subtraction.

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3 years ago

What is log b^b^6x equivalent to (The b is under log and ^b)? How do you know?

Arturiano [62]

Answer: 6x

Work Shown:

For each step, the logs are all base b. This is to save time and hassle of writing tricky notation of having to write the smaller subscript 'b' multiple times. The first rule to use is that log(x^y) = y*log(x) for any base of a logarithm. The second rule is that $\log_b(b) = 1$ meaning that the log base of itself is 1

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3 years ago

How do I find the missing sides in this triangle?

stiv31 [10]

Answer:

This is a 30-60-90 triangle so you would do this formula:

Short side (opposite the 30 degree angle) = x.

Hypotenuse (opposite the 90 degree angle) = 2x.

Long side (opposite the 60 degree angle) = x√3.

Step-by-step explanation:

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3 years ago

MATH HELP...PLz

PilotLPTM [1.2K]

a. 14, 18, 22, 26.... It is +4

b. 2,430, 7,290, 21,870..... It is x3

c. So it is going -2, -4, -6, -8 so the next one would be -10 which is -13 then -12 which is -25 and so on.

Hope this helps!

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4 years ago

Mark the statements that are true.

lara [203]

Answer:

Correct answers:

A. An angle that measures $\frac{\pi}{6}$ radians also measures $30^o$

C. An angle that measures $180^o$ also measures $\pi$ radians

Step-by-step explanation:

Recall the formula to transform radians to degrees and vice-versa:

$\angle\,radians=\frac{\pi}{180^o} \,* \,\angle degrees\\ \\\angle\,degrees=\frac{180^o}{\pi} \,* \,\angle radians$

Therefore we can investigate each of the statements, and find that when we have a $\frac{\pi}{6}$ radians angle, then its degree formula becomes:

$\angle\,degrees=\frac{180^o}{\pi} \,* \,\angle radians\\\angle\,degrees=\frac{180^o}{\pi} \,* \,\frac{\pi}{6} \\\angle\,degrees=\frac{180^o}{6} \\\angle\,degrees=30^o$

also when an angle measures $180^o$ , its radian measure is:

$\angle\,radians=\frac{\pi}{180^o} \,* \,\angle degrees\\\angle\,radians=\frac{\pi}{180^o} \,* \,180^o\\\angle\,radians=\pi$

The other relationships are not true as per the conversion formulas

7 0

3 years ago