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Sedbober [7]
3 years ago
6

Change 1675 grams to kilograms. kg

Mathematics
1 answer:
kati45 [8]3 years ago
7 0

Answer:

The answer is 1.675

Step-by-step explanation:

 I divided the mass value by  1000. There you go, Hope this helps!!!

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Can anyone help me out for this question? Please
MissTica
The answer would be H. All you have to do for a problem like this in the future are to add the 3 different angles together and make sure they equal 180 degrees.
8 0
4 years ago
A tree has a circumference of 16 ft. Calculate the volume of wood it contains if the tree is 10ft tall. Round your answer to the
Veronika [31]

Answer:

Step-by-step explanation:

The circumference of the tree is the distance around the tree's circular top. The formula for determining the circumference of a circle is expressed as

Circumference = 2πr

If the tree has a circumference of 16 ft, it means that

2πr = 16

πr = 16/2 = 8

r = 8/π

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

if the tree is 10ft tall, then the volume of wood it contains is

Volume = π × (8/π)² × 10

Volume = 64/π × 10

Volume = 64/3.14 × 10

Volume = 204 cubic feet

7 0
3 years ago
Help I’ll mark brainliest
lakkis [162]

Answer:

12.04m = l

Step-by-step explanation:

We can use the Pythagorean theorem

a^2 + b^2 =c^2

where a and b are the legs and c is the hypotenuse

12^2 + 1 ^2 = l^2

144 + 1 = l^2

145 = l^2

Take the square root of each side

sqrt(145) = sqrt(l^2)

12.04159458 = l

To the nearest hundredth

12.04m = l

5 0
3 years ago
Read 2 more answers
Among all monthly bills from a certain credit card company, the mean amount billed was $465 and the standard deviation was $300.
Fynjy0 [20]

Answer:

0.02% probability that the average amount billed on the sample bills is greater than $500.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 465, \sigma = 300, n = 900, s = \frac{300}{\sqrt{900}} = 10.

What is the probability that the average amount billed on the sample bills is greater than $500?

This probability is 1 subtracted by the pvalue of Z when X = 500. So

Z = \frac{X - \mu}{s}

Z = \frac{500 - 465}{10}

Z = 3.5

Z = 3.5 has a pvalue of 0.9998.

So there is a 1-0.9998 = 0.0002 = 0.02% probability that the average amount billed on the sample bills is greater than $500.

8 0
3 years ago
3/10
Tom [10]

Answer:

12 adults

Step-by-step explanation:

If a child ticket costs 5 dollars

then 125-5=120

120 divided by 10(the cost of each ticket for an adult)

12

So there are 12 adults

8 0
3 years ago
Read 2 more answers
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