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frutty [35]
3 years ago
15

There are 3 different mathematics courses, 3 different science courses, and 5 different history courses. If a student must take

one of each, how many different ways can this be done?
Mathematics
1 answer:
Damm [24]3 years ago
3 0

Answer:

45 ways

Step-by-step explanation:

We are given;

there are 3 different math courses, 3 different science courses, and 5 different history courses.

Thus;

Number ways to take math course = 3

The number of ways to take science course = 3

The number of ways to take history course = 5

Now, if a student must take one of each course, the different ways it can be done is;

possible ways = 3 x 3 x 5 = 45 ways.

Thus, number of different ways in which a student must take one of each subject is 45 ways.

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Answer:

(−4, 12), (1, −3)

Step-by-step explanation:

y = −3x

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so

x^2 −4 = −3x

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(x + 4)(x - 1) = 0

x + 4 = 0; x = -4

x - 1 = 0; x = 1

when x = 1, y = -3(1) = -3

when x = -4, y = -3(-4) = 12

Answer

(-4 , 12), (1 , -3)

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It would be a right angle
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slamgirl [31]

Answer:

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We can factor out a 1 from -3 to get 5\cdot(-3)=5\cdot-1\cdot3=-1(5\cdot3).

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Find the x- and y-intercepts of the function f(x) = log(2x + 1) − 1.
sleet_krkn [62]
<span>Alright, here's your answer.

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x-intercept is computed by solving f(x) = 0 for x: here that is 
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That’s 10 = 2x + 1 

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I hope I helped! :)

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Add like terms

12x-13x=-24

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