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Viktor [21]
3 years ago
12

Line parallel to y=2x has a slope of ?

Mathematics
2 answers:
loris [4]3 years ago
7 0

In order to find the slope of a line parallel to this one, we must be familiar with the slope/intercept form, which is y= mx + b. M would be the slope. Therefore this line has a slope of 2. Parallel lines have the same slope, therefore<em> a line parallel to y=2x has a slope of </em><em>2</em><em>. </em>

Pavlova-9 [17]3 years ago
4 0
2. The number before x is always the slope! Hope this helps you out.
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Mario invests 1,500 in a savings account that earns 2% interest a year. He also plans to set aside $50 cash a month. A:2100(1.02
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Answer:

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Step-by-step explanation:

x is in years

Let's just think about the investment of 1500 in an account earning 2% per year.

Before the years even start, you are at 1500 ( present value).

The next year (year 1), it would be 1500*.02+1500=(1500)(1.02).

The next year (year 2), it would be 1500(1.02)(.02)+1500(1.02)=1500(1.02)(1.02).

We keep multiplying factors of (1.02) each time.

So for year x, you would have saved 1500(1.02)^x.

Now we are saving 50 cash per month. Per year this would be 12(50) since there are 12 months in a year.  12(50)=600.  

So the first year you would have 600.

The second year you would have 600(2) or 1200.

The third year you would have 600(3) or 1800.

Let's put this together:

1500(1.02)^x  +   600x

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Suppose h(t) = -4t^2+ 11t + 3 is the height of a diver above the water in
nadezda [96]

Answer:

11/4 seconds

Step-by-step explanation:

We can see from the given equation that the height at the diving board is h = 3.

This is because the h(t) equation has that +3 at the end, which denotes the initial height of the diver, the height when he is standing on the board before jumping.

To find where h(t) = 3 is true, we need to set h(t) equal to 3 and solve for t.

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so h(t) = 3 when t = 0 and when t = 11/4 sec

we already know that at t = 0 the height is 3, it is the initial height given from the equation, so we want to use the other solution for t.

the diver is back at the height of the diving board at t = 11/4 sec

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