We know that
to find the equation of a line i need two points
let
point A-----> (-21,10)
point B-----> (-28,14)
step 1
find the slope m
m=(y2-y1)/(x2-x1)-----> m=(14-10)/(-28+21)----> m=-4/7
step 2
find the equation of a line with
m=-4/7 and the point A (-21,10)
y-y1=m*(x-x1)------> y-10=(-4/7)*(x+21)---> y=(-4/7)x-12+10
y=(-4/7)x-2
step 3
find x intercept
for y=0
y=(-4/7)x-2------> 0=(-4/7)x-2-----> 4/7x=-2----> x=-14/4----> x=-3.5
the x intercept is (-3.5,0)
step 4
find the y intercept
for x=0
y=(-4/7)x-2--------> y=-2
the y intercept is (0,-2)
the answers arethe x intercept is (-3.5,0)the y intercept is (0,-2)
see the attached figure
Answer:
The value of k is -11
Step-by-step explanation:
If (x+2) is a factor of x3 − 6x2 + kx + 10:
Then,
f(x)=x3 − 6x2 + kx + 10
f(-2)=0
f(-2)=(-2)³-6(-2)²+k(-2)+10=0
f(-2)= -8-6(4)-2k+10=0
f(-2)= -8-24-2k+10=0
Solve the like terms:
f(-2)=-2k-22=0
f(-2)=-2k=0+22
-2k=22
k=22/-2
k=-11
Hence the value of k is -11....
The domain is {-7,-5,-3,0,7}.
The range is {-1,-1,2,3,6}.
:) hope you get a good grade.
Terms: -4j, -2, -5j, 6
Like Terms: -4j and -5j, -2 and 6
Coefficients: -4, -5
Constants: -2, 6
C
Due to the fact that it is starting from 0 and moving in a steady pattern