Identify the cross section of the cube shown in the diagram
1 answer:
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Answer:
40 pounds of nuts worth $1.60
60 pounds of nuts worth $1.85
Step-by-step explanation:
This is a mixture problem, so see the attachment below:
<u><em>*Sorry if it's unclear, but I hope it helps!</em></u>
Answer:
B. -1
Step-by-step explanation:
x^3-4x^2+2x+10=x^2-5x-3
We know it has 3 roots since it is a 3rd degree polynomial.
Two of the roots are (3+2i) and (3-2i)
Subtract x^2-5x-3 from both sides
x^3-4x^2+2x+10-(x^2-5x-3)=x^2-5x-3 -(x^2-5x-3)
Distribute the minus sign
x^3-4x^2+2x+10-x^2+5x+3=x^2-5x-3 -x^2+5x+3
x^3 -5x^2+7x +13 =0
Graphing this equation , we see that it crosses the x axis at x=-1
That covers the three roots, 1 real and two complex
Assuming that we are performing a two-tailed test, the significance level is α = 0.1 would be dispersed in the distribution's tails with α/2 = 0.05.
And we must consider two critical values that add up to 0.05 of a area on every tail of a F distribution with a 10 degree angle.
An F statistic is one that is ascertained through an ANOVA test. It helps determine the relevance of the variable groups.
Now, according to the question;
We understand that sample size for numerator is 11 and also the sample size for denominator is 7. So, for each case, we can calculate a degrees of freedom as follows:
In this case, the F distribution could have 10 degrees of freedom with in numerator as well as 6 degrees of freedom in the denominator.
Assuming we are conducting a two-tailed test, the significance level of α = 0.1 will be distributed in the tails of the distribution with α/2 = 0.05.
Now, locate two critical values that collect 0.05 of a area on every tail of F distribution to 10 degrees of freedom again for numerator and 6 degrees of freedom for the denominator and we obtained using a table or excel;
Therefore, the critical f-value for the two-tailed experiment is found.
To know more about the critical f-value, here
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