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svetoff [14.1K]
3 years ago
9

1,114,040 in word form

Mathematics
1 answer:
Vadim26 [7]3 years ago
4 0

Answer:

one million, one hundred fourteen thousand, forty

Step-by-step explanation:

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There is a bag with only red marbles and blue marbles.
Genrish500 [490]

Answer:

49 red marbles

Step-by-step explanation:

We should first make 5/12 have a base of 84, so that'll be

(5*7)/(12*7)=35/84. So we have 35 blue marbles and all the rest are red, so 84-35=49

DUBS

Please consider giving me a brainliest! Thank you.

7 0
2 years ago
A right triangle has side 10 and hypotenuse 26. Use the Pythagorean Theorem
alekssr [168]

Answer:

24

Step-by-step explanation:

The Pythagorean Theorem states that a^{2} +b^{2} =c^{2} where a and b are the legs in a right triangle and c is the hypotenuse. Therefore, just substitute the values a = 10 and c = 26 into the equation to get b = 24

Hope this helps :)

3 0
2 years ago
The least total cost method (LTC) lot-sizing technique calculates the order quantity by comparing the carrying cost and the setu
rewona [7]

Answer:

True

Step-by-step explanation:

The least total cost method is the method in which the total cost of the ordering cost and the total carrying cost is equal among various lot size available.

The order quantity should be choose when the total ordering cost and the total carrying cost equal to each other

The formula to compute the economic order quantity is shown below:

a. The computation of the economic order quantity is shown below:

= \sqrt{\frac{2\times \text{Annual demand}\times \text{Ordering cost}}{\text{Carrying cost}}}

It is always be expressed in units

The formula to compute the ordering cost is

= \frac{Annual\ demand}{Economic\ order\ quantity}\times ordering\ cost\ per\ order

And, the formula to compute the carrying cost is

= \frac{Economic\ order\ quanity}{2}\times carrying\ cost\ per\ unit

Hence, the given statement is true

8 0
3 years ago
Help me please just help I need help rn like rn
alexgriva [62]

Answer:

i.900

j.6

k.8

l.0

Step-by-step explanation:

hope this helps you ;)

6 0
2 years ago
We have two fair three-sided dice, indexed by i = 1, 2. Each die has sides labeled 1, 2, and 3. We roll the two dice independent
Bogdan [553]

Answer:

(a) P(X = 0) = 1/3

(b) P(X = 1) = 2/9

(c) P(X = −2) = 1/9

(d) P(X = 3) = 0

(a) P(Y = 0) = 0

(b) P(Y = 1) = 1/3

(c) P(Y = 2) = 1/3

Step-by-step explanation:

Given:

- Two 3-sided fair die.

- Random Variable X_1 denotes the number you get for rolling 1st die.

- Random Variable X_2 denotes the number you get for rolling 2nd die.

- Random Variable X = X_2 - X_1.

Solution:

- First we will develop a probability distribution of X such that it is defined by the difference of second and first roll of die.

- Possible outcomes of X : { - 2 , -1 , 0 ,1 , 2 }

- The corresponding probabilities for each outcome are:

                  ( X = -2 ):  { X_2 = 1 , X_1 = 3 }

                  P ( X = -2 ):  P ( X_2 = 1 ) * P ( X_1 = 3 )

                                 :  ( 1 / 3 ) * ( 1 / 3 )

                                 : ( 1 / 9 )

   

                  ( X = -1 ):  { X_2 = 1 , X_1 = 2 } + { X_2 = 2 , X_1 = 3 }

                 P ( X = -1 ):  P ( X_2 = 1 ) * P ( X_1 = 3 ) + P ( X_2 = 2 ) * P ( X_1 = 3)

                                 :  ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

                                 : ( 2 / 9 )

         

       ( X = 0 ):  { X_2 = 1 , X_1 = 1 } + { X_2 = 2 , X_1 = 2 } +  { X_2 = 3 , X_1 = 3 }

       P ( X = -1 ):P ( X_2 = 1 )*P ( X_1 = 1 )+P( X_2 = 2 )*P ( X_1 = 2)+P( X_2 = 3 )*P ( X_1 = 3)

                                 :  ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

                                 : ( 3 / 9 ) = ( 1 / 3 )

       

                    ( X = 1 ):  { X_2 = 2 , X_1 = 1 } + { X_2 = 3 , X_1 = 2 }

                 P ( X = 1 ):  P ( X_2 = 2 ) * P ( X_1 = 1 ) + P ( X_2 = 3 ) * P ( X_1 = 2)

                                 :  ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

                                 : ( 2 / 9 )

                    ( X = 2 ):  { X_2 = 1 , X_1 = 3 }

                  P ( X = 2 ):  P ( X_2 = 3 ) * P ( X_1 = 1 )

                                    :  ( 1 / 3 ) * ( 1 / 3 )

                                    : ( 1 / 9 )                  

- The distribution Y = X_2,

                          P(Y=0) = 0

                          P(Y=1) =  1/3

                          P(Y=2) = 1/ 3

- The probability for each number of 3 sided die is same = 1 / 3.

7 0
3 years ago
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