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marshall27 [118]
3 years ago
14

Peter scored 30 goals at soccer practice. His ratio of goals to misses was 6:7. How many times did he miss?

Mathematics
2 answers:
Fiesta28 [93]3 years ago
6 0
Goals=30
the ratio is 6 units to 7 units
goals=6 units
goals=30
30=6 uints
divide by 6
5=1 unit
so miss=7 units
5 per unit times 7 units=35
answer is 35 miss
soldier1979 [14.2K]3 years ago
6 0
He missed 26 times. First you do 6 divided by 7 times 100 to get 86(rounded). Then you do 30 divided by 100 to get .3 times the 86 to get 26.
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Step-by-step explanation:

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x - 3 = 2

x = 5

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(5, 4) coordinates for B

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3 years ago
0.06 + 2 =
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Answer:

1.) 2.06

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10.) 3.05

11.) 1.3

12.) 0.2

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14.) 0.4

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Step-by-step explanation:

Simple addition with decimals. If you have a whole number like 5, with a decimal like 0.07, 5+0.07 would be 5.07. 5 would take the spot of 0 in the ones place and .07 would remain. If you have 0.10+0.8, it would be 0.9 as your answer since we make 0.8 to 0.80 or 0.10 to 0.1 and add the two together. Hope this helped!

3 0
2 years ago
Mike runs cross country. He runs 7 miles in 56
kondor19780726 [428]
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Every day annabelle takes the train to work, she uses an app to charge the parking fee shown to her credit card. What will be he
anastassius [24]

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3 0
3 years ago
CCA has stated in 2017 that 36.5 % of its students are first generation college students.Suppose you sample 15 CCA students and
nignag [31]

Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x = r) = nCr × p^r × q^(n - r)

Where

x represent the number of successes.

p represents the probability of success.

q = (1 - p) represents the probability of failure.

n represents the number of trials or sample.

From the information given,

p = 36.5% = 36.5/100 = 0.365

q = 1 - p = 1 - 0.365

q = 0.635

n = 15

a) P(x = 0) = 15C0 × 0.365^0 × 0.635^(15 - 0) = 0.0011

P(x = 1) = 15C1 × 0.365^1 × 0.635^(15 - 1) = 0.0095

P(x = 2) = 15C2 × 0.365^2 × 0.635^(15 - 2) = 0.038

P(x = 3) = 15C3 × 0.365^3 × 0.635^(15 - 3) = 0.095

P(x = 4) = 15C4 × 0.365^4 × 0.635^(15 - 4) = 0.16

P(x = 5) = 15C5 × 0.365^5 × 0.635^(15 - 5) = 0.21

k P(X = k)

0 0.0011

1 0.0095

2 0.038

3 0.095

4 0.16

5 0.21

b) mean = np = 15 × 0.365 = 5.475

c) standard deviation = √npq

= √15 × 0.365 × 0.635

= 1.86

d) z = (x - mean)/standard deviation

x = 2

z = (2 - 5.475)/1.86 = - 1.87

6 0
3 years ago
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