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grandymaker [24]
2 years ago
6

Find the equation of the exponential function represented by the table below

Mathematics
1 answer:
DENIUS [597]2 years ago
3 0

Answer:

hhgghjhbbhhhgghjsdnsnss

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I need help asparagus is it a b c d please help me
Yuri [45]

Answer:

A

Step-by-step explanation:

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3 years ago
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What is the rate of change for the sequence shown below. (1,2) (2,2.5) (3,3) (4,3.5) (5,4)
Nataly [62]

Answer:

0.5

Step-by-step explanation:

The given ordered pairs are: (1,2) (2,2.5) (3,3) (4,3.5) (5,4)

The corresponding sequence is :

2,2.5,3,3.5, 4,....

We can see that there is a common difference of d=0.5.

Better still we could use the slope formula:

m =  \frac{y_2-y_1}{x_2-x_1}

We substitute the point (1,2) and (2,2.5).

The rate of change of this sequence is:

m =  \frac{2.5 - 2}{2 - 1}  =  \frac{0.5}{1}  = 0.5

5 0
3 years ago
C. The King football team ordered 50 hats. The cost of shipping was
kari74 [83]
The answer is $4.99 each
6 0
3 years ago
Compute the loss of head and pressure drop in 200 ft of horizontal 6-in diameter asphalted cast iron pipe carrying water with a
laiz [17]

Answer:

The answer is below

Step-by-step explanation:

12 inches = 1 ft.

6 inches = 6 inches * (1 ft./12 inches) = 0.5 ft.

Therefore the diameter of the cast iron (D) = 6 inches = 0.5 ft.

The area of cast iron (A) = πD²/4 = π(0.5)²/4 = 0.196 ft²

The velocity (V) = 6 ft./s, the acceleration due to gravity (g) = 32.2 ft./s²

ε/D = 0.0004 ft./ 0.5 ft. = 0.0008

Using the moody chart, find the line ε/D = 0.0008 and determine the point of intersection with the vertical line R = 2.7 * 10⁵. Hence we get f = 0.02.

The head loss (h) is:

h_f=f*\frac{L}{d}* \frac{V^2}{2g}=0.02*\frac{200\ ft}{0.5\ ft} *\frac{(6\ ft/s)^2}{2*32.2\ ft/s^2}=4.5\ ft

The pressure drop (Δp) is:

Δp = ρgh_f = (62.4\ lbf/ft^3)(4.5\ ft)= 280\ lbf/ft^2

5 0
3 years ago
Janet wanted to determine her average phone call length over 90 days. She collected the phone bills and randomly picked ten entr
muminat

oops sorry wrong question. sorry if I confused anyone :(

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2 years ago
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