Answer:
Jay started with $148.5 and Kay with $24.75.
Step-by-step explanation:
With the information provided you know that Jay had 6 times as much money as Kay wich can be expressed as:
J=6K, where
J is the money Jay had
K is the money Kay had
Also, you know that Jay gave Kay $33 and Jay now has twice as much money as Kay, which would be:
J-33=2(K+33)
Now, you can replace J=6K in this equation and solve for K:
6K-33=2K+66
6K-2K=66+33
4K=66
K=24.75
Then, you can replace the value of K in J=6K:
J=6*24.75
J=148.5
According to this, the answer is that Jay started with $148.5 and Kay with $24.75.
Answer:
B
Step-by-step explanation:
x² + 9x
to complete the square
add ( half the coefficient of the x- term )² to x² + 9x
= x² + 2(
)x + ( )²
= x² + 9x + 
← the value of c
= (x + )² ← a perfect square
Subtract the amount used from the total packets:
5000 - 1824 = 3176 left after the first week.
3176 - 2352 = 824 total packets left.
Answer:
ntersecting lines DA and CE.
To find:
Each pair of adjacent angles and vertical angles.
Solution:
Adjacent angles are in the same straight line.
Pair of adjacent angles:
(1) ∠EBD and ∠DBC
(2) ∠DBC and ∠CBA
(3) ∠CBA and ∠ABE
(4) ∠ABE and ∠EBD
Vertical angles are opposite angles in the same vertex.
Pair of vertical angles:
(1) ∠EBD and ∠CBA
(2) ∠DBC and ∠EBA
Answer:
The answer is C.
Step-by-step explanation:
I would simplify the expression first.
Equation: (6m^-1)^-3
You can get rid of n^0 because that equals 1.
Any expression raised to the power of -1 equals its reciprocal.
Equation: (6/m)^-3
Equation: (m/6)^3
Final Equation: m^3/216
Now, plug in 3.
(3)^3/216.
27/216 = 1/8
Hope this helps!
