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4 years ago

Points -3,2 rotated 90 clockwise its a maze i need help o thank u

Mathematics

1 answer:

SCORPION-xisa [38]4 years ago

6 0

Answer:

(2,3)

Step-by-step explanation:

Rotation through 90 clockwise gives the expression

( x , y )___ ( y ,- x )

so when you put the points -3 ,2 in the relation , it becomes

( -3 , 2 ) ___ ( 2, - -3 )

= ( x, y ) __ ( 2, 3 ). meaning when you rotate -3,2 through 90 clockwise you will get the image ( 2 ,3 )

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The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen

vfiekz [6]

Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.75$

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X = 9)$ when $n = 12$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581$

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X \geq 16)$ when $n = 20$

$P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 16) = C_{20,16}.(0.75)^{16}.(0.25)^{4} = 0.1897$

$P(X = 17) = C_{20,17}.(0.75)^{17}.(0.25)^{3} = 0.1339$

$P(X = 18) = C_{20,18}.(0.75)^{18}.(0.25)^{2} = 0.0669$

$P(X = 19) = C_{20,19}.(0.75)^{19}.(0.25)^{1} = 0.0211$

$P(X = 20) = C_{20,20}.(0.75)^{20}.(0.25)^{0} = 0.0032$

$P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1897 + 0.1339 + 0.0669 + 0.0211 + 0.0032 = 0.4148$

c. If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

$E(X) = np$

In this question, we have $n = 22$

$E(X) = 22*0.75 = 16.5$

The closest integer to 16.5 is 17.

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3 years ago

Jade buys a blouse and a skirt for 3/4 of their original price. Jade pays a total of $31.50 for the two items. If the original p

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3/4 times 18= 13.5
31.5-13.5=18
It cost 18 dollars for the skirt with a discount.
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If you set up a proportion to find the original price of the skirt you will get the answer.
18/x=75/100
75x=18 times 100
75x=1800
75x/75=1800/75
x=24
The original price of the skirt is 24 dollars.

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3 years ago

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z = √(6^2 + 9^2)

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z = √117

z = 3√13 = 10.8

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x/6 = 6/9

Cross multiply:

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Divide both sides by 9:

x = 36/9

x = 4

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