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3 years ago

To the nearest degree, what is the measure of each exterior angle of a regular octagon? O A. 45° O B. 30° O C. 51o O D. 60°

Mathematics

2 answers:

LekaFEV [45]3 years ago

7 0

Answer:

The measure of each exterior angle of a regular octagon is A. 45°

Step-by-step explanation:

To find the solution to the problem above, we will follow the steps below;

To find the exterior angle of a regular polygon we can simply divide 360 by the number of sides of that polygon or we can simply use the formula below

Each Exterior angle = 360/n

where n is the number of sides

an octagon is an eight-sided polygon. This implies that the number of side =8

Each Exterior angle = 360/n

=360/8

=45°

The measure of each exterior angle of a regular octagon is 45°

riadik2000 [5.3K]3 years ago

3 0

Because an octagon consists of eigth sides/edges, and 360 degrees is the total sum of the angles, we simply divide 360 by 8:

360/8 = 45.

Option A, 45 degrees

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Roderick wants to draw a circle for which the numerical value of the circumference is greater than the value of the area. Which

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The best way to justify which answers are correct are to calculate the circumference and the area for each of the circles with the given radii. I organized this information into a chart.

Circumference | Area

1/2 3.14 0.785

1 6.28 3.14

1 1/2 9.42 7.065

2 12.56 12.56

2 1/2 15.7 19.625

The first three choices will result in a numerical value for the radius that is smaller than the area.

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3 years ago

If the last 2 months of the year each have the most common amount of rainfall, how much more rain will fall for the year?

miss Akunina [59]

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for value b the quadratic equation

${2x}^{2} + bx + 3 = 0 \: has \: two \: the \: distanct \: root$

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2 years ago

Complete the following table for residuals for the exponential function: f(x) = 49.3(1.47)

agasfer [191]

Answer:

Predicted values:

$\hat y_1 = 49.3 (1.47)^1 =72.471$

$\hat y_2 = 49.3 (1.47)^2 =106.5324$

$\hat y_3 = 49.3 (1.47)^3 =156.6026$

$\hat y_4 = 49.3 (1.47)^4 =230.2058$

$\hat y_5 = 49.3 (1.47)^5 =338.4025$

$\hat y_6 = 49.3 (1.47)^6 =497.4517$

$\hat y_7 = 49.3 (1.47)^7 =731.254$

$\hat y_8 = 49.3 (1.47)^8 =1074.943$

Residuals:

$e_1 = 65-72.471=-7.471$

$e_2 = 90-106.5324=-16.5324$

$e_3 = 162-156.6026 = 5.3974$

$e_4 = 224-230.2058 = -6.2058$

$e_5 = 337-338.4025 = -1.4025$

$e_6 = 466-497.4617 = -31.4517$

$e_7 = 780-731.254 = 48.7459$

$e_8 = 1087-1074.493 = 12.0566$

Step-by-step explanation:

For this case we assume the following exponential function:

$\hat y_i = 49.3 (1.47)^x$

Where x represent the hours and y the predicted values for each hour. We can find the estimated values like this:

$\hat y_1 = 49.3 (1.47)^1 =72.471$

$\hat y_2 = 49.3 (1.47)^2 =106.5324$

$\hat y_3 = 49.3 (1.47)^3 =156.6026$

$\hat y_4 = 49.3 (1.47)^4 =230.2058$

$\hat y_5 = 49.3 (1.47)^5 =338.4025$

$\hat y_6 = 49.3 (1.47)^6 =497.4517$

$\hat y_7 = 49.3 (1.47)^7 =731.254$

$\hat y_8 = 49.3 (1.47)^8 =1074.943$

Now we can find the residuals with this formula:

$e_i = Y_i -\hat y_i$

And replacing we got:

$e_1 = 65-72.471=-7.471$

$e_2 = 90-106.5324=-16.5324$

$e_3 = 162-156.6026 = 5.3974$

$e_4 = 224-230.2058 = -6.2058$

$e_5 = 337-338.4025 = -1.4025$

$e_6 = 466-497.4617 = -31.4517$

$e_7 = 780-731.254 = 48.7459$

$e_8 = 1087-1074.493 = 12.0566$

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3 years ago

Suppose a basketball player has made 233 out of 402 free throws. if the player makes the next 3 free throws, i will pay you $166

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The expected value is $0.11.

The probability that the player will make the next free throw is 233/402. The probability that the next 3 are made will be (233/402)^3. To find the expected value of this, we multiply by the winnings we would have in this case, 166. So far we have:

((233/402)^3)(166)

The probability that the next 3 are not made is 1-((233/402)^3). Multiply this by the loss, -40, to get its expected value. This gets us to:

((233/402)^3)(166)-(1-((233/402)^3)).

This comes out to $0.11.

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4 years ago

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