Answer:
20.25 m²
Step-by-step explanation:
the area (A) and circumference (C) of a circle are calculated using the formulae
C = 2πr and A = πr² ( where r is the radius )
calculate the radius using the formula for circumference
2πr = 9π ( divide both sides by 2π )
r = = = 4.5, hence
A = π × 4.5² = 20.25π m²
Remember that when multiplying fractions, we multiply everything on the top and everything on the bottom.
a * b * c
(-2 / 5) * (20 / 32) * (-4 / 10)
(-2 * 20 * -4) / (5 * 32 * 10)
160 / 1600
1 / 10
Correct answer: D. 1/10
Hope this helps!! :)
Answer:
a. linear pair 5 & 6
b. pair of vertical angles 5 & 2
c. pair of angles that are congruent 3 & 8
Step-by-step explanation:
A linear pair of angles is formed when two lines intersect.
Vertical angles are a pair of non-adjacent angles formed by the intersection of two straight lines. In simple words, vertical angles are located across from one another in the corners of the "X" formed by two straight lines.
If two angles are complements of the same angle (or congruent angles), then the two angles are congruent. All right angles are congruent.
Asymptote at x = 3 and a horizontal asymptote at y = 1. The curves approach these asymptotes but never cross them. The method used to find the horizontal asymptote changes depending on how the degrees of the polynomials in the numerator and denominator of the function compare.
Answer:
67.5feet
Step-by-step explanation:
Given parameters:
Model distance between building and gymnasium = 22.5 inches
Scale of model : 1 inch = 3 feet
Unknown:
Actual ground distance = ?
To solve this problem, we first must understand the concept of scale. A scale is a relationship that represents a dimension on a map/model compared to the true ground expression. In order to visualize or represent some real life objects on paper or in a computer, we use models. These models are an abstraction of the real world based on scales. There are different ways of representing a scale.
In this problem;
the scale is given as;
1 inch on model represents 3 feet on ground
Now, to find 22.5 inches, simply cross multiply and solve;
If 1 inch on model represents 3 feet on ground
22.5 inches on a model will be = 
= 67.5feet
Therefore, the actual distance is 67.5feet
