Teresa exercises at least 35 minutes per day.

V=S^3 S=20 please help me lol

Otrada [13]

Hi there!

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I believe your answer is:

V = 8,000

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Here’s why:

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$\boxed{\text{Evaluating...}}\\\\V=s^3\\-----------\\\rightarrow V=(20)^3\\\\\rightarrow V = 20 * 20 * 20 \\\\\rightarrow V = 8,000$

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Hope this helps you. I apologize if it’s incorrect.

4 0

3 years ago

By the end of the summer, Sarah will earn $420 doing yard work. If she deposits this amount in a savings account paying 3.5% sim

valina [46]

If you use the equation for interest, you get $493.50

7 0

4 years ago

Read 2 more answers

1. At a computer manufacturing company, the actual size of a computer chip is normally distributed with a mean of 1 cm and a sta

liraira [26]

Answer:

The 4 answers are given below:

0.1cm, 0.1 probability, 0.25 probability, 1.095cm

Step-by-step explanation:

QUESTION HEAD: At a computer manufacturing company, the actual size of a computer chip is normally distributed with a mean of 1cm and standard deviation of 0.1cm. A random sample of 12 computer chips is taken.

(A) What is the standard error for the sample mean?

(B) What is the probability that the sample mean will be between 0.99 and 1.01cm?

(C) What is the probability that the sample mean will be below 0.95cm?

(D) Above what value do 2.5% of the sample means fall?

ANSWERS:

(A) The standard error for the sample mean is 0.1cm

(B) [0.99, 1.01]cm?

The mean length is 1cm and S.E. is 0.1cm, hence all lengths fall into the following range: [0.9 - 1.1]

0.99 - 0.9 = 0.09

1.1 - 1.01 = 0.09

0.09 + 0.09 = 0.18

1.1 - 0.9 = 0.2

0.2 - 0.18 = 0.02 This is the fraction of 0.2 that the length bracket in the question occupies. So 0.02/0.2 = 0.1

Hence the probability that the sample mean will be between 0.99 and 1.01cm is 0.1 (which translates to a 10% probability/chance)

(C) The probability that the sample mean will be below 0.95 is:

0.95 - 0.9 = 0.05

0.05/0.2 = 0.25 (which translates to a 25% chance of occurrence)

(D) Above what value do 2.5% of the sample means fall?

Here, you're looking for the value of the mean which serves as the lower limit for the top 2.5% of sample mean values.

2.5% of 0.2 = 0.025 × 0.2 = 0.005

Subtract this from the highest possible mean value:

1.1 - 0.005 = 1.095

So, above 1.095 is where 2.5% of the sample means fall

3 0

3 years ago

Linear functions are hard (._.)

Pani-rosa [81]

I know right

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

2+x5-3=(2+)x(5-3) is the equation true or not show work why

VLD [36.1K]

This equation has some nested grouping symbols on the left-hand side. As usual, I'll simplify from the inside out. I'll start by inserting the "understood" 1 in front of that innermost set of parentheses:

3 + 2[4x – (4 + 3x)] = –1

3 + 2[4x – 1(4 + 3x)] = –1

3 + 2[4x – 1(4) – 1(3x)] = –1

3 + 2[4x – 4 – 3x] = –1

3 + 2[1x – 4] = –1

3 + 2[1x] + 2[–4] = –1

3 + 2x – 8 = –1

2x + 3 – 8 = –1

2x – 5 = –1

2x – 5 + 5 = –1 + 5

2x = 4

x = 2
It is not required that you write out this many steps; once you get comfortable with the process, you'll probably do a lot of this in your head. But until you reach that comfort zone, you should write things out at least this clearly and completely.

Always remember, by the way, that you can check your answers in "solving" problems by plugging the numerical answer back in to the original equation. In this case, the variable is only in terms on the left-hand side (LHS) of the equation; my "check" (that is, my evaluation at the solution value) looks like this:

LHS: 3 + 2[4x – (4 + 3x)]:

3 + 2[4(2) – (4 + 3(2))]

3 + 2[8 – (4 + 6)]

3 + 2[8 – (10)]

3 + 2[–2]

3 – 4

–1
Since this is what I was supposed to get for the right-hand side (that is, I've shown that the LHS is equal to the RHS), my solution value was correct.

3 0

3 years ago