What is the sum of sq root -2 and sq root -18?
1 answer:
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Given:
The equation of given line is
A line is perpendicular to the given line and passes through the point (9,5).
To find:
The equation of the perpendicular line.
Solution:
We have,
On comparing this equation with slope intercept form , we get
It means, the slope of the given line is 3.
The product of slopes of two perpendicular lines is -1.
Point slope form of a line is
Where, m is the slope.
The slope of perpendicular line is and it passes through the point (9,5). So the equation of the line is
Adding 5 on both sides, we get
Therefore, the equation of required line is .
Our polynomial is 
We can tell from -28 that the binomials are one positive and one negative.
We can use a factoring chart. What adds to make +3x and multiplies to make -28.
To get a negative 28, we can multiply -4 and positive seven, which add together after being multiplied by x to get +3x. Therefore, you are left with (x+7) and (x-4).
We can tell from -28 that the binomials are one positive and one negative.
We can use a factoring chart. What adds to make +3x and multiplies to make -28.
To get a negative 28, we can multiply -4 and positive seven, which add together after being multiplied by x to get +3x. Therefore, you are left with (x+7) and (x-4).