P(t)=6t
A(p)=πp^2, since p(t)=6t
A(t)=π(p(t))^2
A(t)=π(6t)^2
A(t)=36πt^2, so when t=8 and approximating π≈3.14
A(8)≈36(3.14)(8^2)
A(8)≈36(3.14)64
A(8)≈7234.56 u^2
Answer:
Like terms are similar and terms are different.
Like terms :-
They are similar.
Terms :-
One has an exponent and other does not which means they are not like terms and are only terms.
Hope this helps, thank you :) !!
C. it's simple dude. you just plug in each matrix value into the given function and solve. the matrix in C matches the given formula.