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Dima020 [189]
4 years ago
15

isabel thinks she has space for a 45 inch wide book case it turns out she only has space for a 40 inch wide book case what is th

e percent error in isabels measurement
Mathematics
1 answer:
Minchanka [31]4 years ago
6 0

Answer:

The percent error in Isabel's measurement is <u>12.5%</u>.

Step-by-step explanation:

Given:

Isabel thinks she has space for a 45 inch wide bookcase it turns out she only has space for a 40 inch wide bookcase.

Now, to find the percent error in Isabel's measurement.

Measurement she thinks = 45 inch.

The actual measurement = 40 inch.

<u><em>So, the error in measurement</em></u> = 45-40=5\ inch.

Now, to get the percent error of the measurement:

\frac{5}{40} \times 100

=\frac{500}{40}

=12.5\%.

Therefore, the percent error in Isabel's measurement is 12.5%.

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therefore, a + b + c = 180°


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What is 8 3/4 % expressed as a fraction?
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For every 10 cars in a parking lot there are 12 trucks. What is the ratio of cars to total vehicles in the parking lot?
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12:10

Step-by-step explanation:

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Ms. Snyder is giving a 28-question test that is made up of multiple choice questions worth 2 points each and open response quest
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Answer:

x *2 + (28-x)*4 = 100

Step-by-step explanation:

Given

Total number of questions in the paper = 28

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Also, the complete test is of 100 marks

Thus, the linear equation representing the

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Write an equation for each context. Draw a model first if necessary, and make sure you define your variable and what it represen
natta225 [31]

Answer:

a. 6x+1240=12484

b.

x_1+x_2+x_3+x_4=65\\x_2=2x_1\\x_3=x_1+2\\x_4=0.25x_2

c. 5x+20=415

Step-by-step explanation:

a. In the account are 6 deposits of the paid that Tom gets each month and the initial $1240. Let x be the paid Tom gets each month, then:

6x+1240=12484

Solving for x:

6x=12484-1240\\6x=11244\\x=\frac{11244}{6} \\x=1874\\

b)Let x_1 be pounds contained in the first box, x_2 the pound in the second box, x_3 the pounds in the third box and x_4 the pound in the fourth box, then:

x_1+x_2+x_3+x_4=65\\x_2=2x_1\\x_3=x_1+2\\x_4=0.25x_2

Substitute the value of x_2 in the last equation:

x_4=0.25(2x_1)\\x_4=0.5x_1

Substitute all the equation in the first and solve for x_1:

x_1+(2x_1)+(x_1+2)+(0.5x_1)=65\\4.5x_1=65-2\\x_1=63/4.5=14

Solving for x2,x3, and x4:

x_2=2x_1=2*14=28\\x_3=x_1+2=14+2=16\\x_4=0.25x_2=0.25*28=7

c) Simon is ordering 5 cans and 5 racquets, the total from the cans is 5(4)=$20. Let x be the cost of each racquet,

5x+20=415

Solving for x:

5x=415-20\\x=395/5=79

3 0
3 years ago
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