You are running a fuel economy study. One of the cars you find is blue. It can travel 30 and one half miles30 1 2 miles on 1 and one fourth gallons1 1 4 gallons of gasoline. Another car is red. It can travel 25 and three fifths miles25 3 5 miles on four fifths gallon 4 5 gallon of gasoline. What is the unit rate for miles per gallon for each car? Which car could travel the greater distance on 1 gallon1 gallon of gasoline?
Blue car: 30.5 / 1.25 =24.4 miles per gallon
Red car: 25.6/0.80 =32 miles per gallon
You can easily see that the Red car travel farther on 1 gallon of gasoline.
Answer:
a) 13 m/s
b) (15 + h) m/s
c) 15 m/s
Step-by-step explanation:
if the location is
y=x²+3*x
then the average velocity from 3 to 7 is
Δy/Δx=[y(7)-y(3)]/(7-3)=[7²+3*7- (3²+3*3)]/4= 13 m/s
then the average velocity from x=6 to to x=6+h
Δy/Δx=[y(6+h)-y(6)]/(6+h-6)=[(6+h)²+3*(6+h)- (6²+3*6)]/h= (2*6*h+3*h+h²)/h=2*6+3= (15 + h) m/s
the instantaneous velocity can be found taking the limit of Δy/Δx when h→0. Then
when h→0 , limit Δy/Δx= (15 + h) m/s = 15 m/s
then v= 15 m/s
also can be found taking the derivative of y in x=6
v=dy/dx=2*x+3
for x=6
v=dy/dx=2*6+3 = 12+3=15 m/s
Answer
creon queens B. lo siento is me equivoco
<em>The answer is Ms Hernandez can bring up to 6 people to the zoo.</em>
<em />
<em>x - the number of people that she can bring to the zoo</em>
<em>The parking will cost $7: a = 7</em>
<em>Admission tickets will cost $15.50 per person: b = 15.50x</em>
<em>She can spend on parking and admission tickets $100:</em>
a + b ≤ 100
a = 7
b = 15.50x
7 + 15.50x ≤ 100
15.50x ≤ 100 - 7
15.50x ≤ 93
x ≤ 93 / 15.50
x ≤ 6
If this shape is trapezium
m (<D) = m (<C)
since AB parallel to CD
m (<C) + m (<A) = 180°
m (<C) = 180 - 125 = 55°
m (<D) = 55°
mark me as brainlest, please
