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disa [49]
3 years ago
9

These three please, thank you!

Mathematics
2 answers:
Lerok [7]3 years ago
5 0

1. 0.01

2. 29.44

3. (69+6)/9

Inessa05 [86]3 years ago
3 0
The first one is 9/25
The second one is 29.44
The last one is 8
You might be interested in
In a couple of sentences and in your own words describe in what ways horizontal, vertical, and oblique asymptotes can be identif
drek231 [11]
A horizontal asymptote is one in which y has a limit as x approaches positive or negative infinite. It is usually due to both the denominator and the numerator having the same highest degree term, and the coefficient created by their proportion serves as the asymptote. For example, (2x^2 + 1) / (3x^2) would have a horizontal asymptote of 2/3

A vertical asymptote is an x value at which y approaches infinite. One example includes when the denominator of the function approaches zero at a certain point. For example, (x^2 + 3) / (x + 1) has a vertical asymptote at x=-1, since the denominator approaches zero as x approaches this point. 

For an oblique asymptote, y generally takes the form of a linear function as x approaches infinite. This is the case when the highest term in numerator is one degree higher than the highest degree term in the denominator. 

Examples include (5x^2 + 2) over 2x, where the oblique asymptote is (5/2)x, and even the linear function 2x+3 has an oblique asymptote of 2x
5 0
3 years ago
A population has a mean, μ = 89 and a standard deviation,σ = 24.
Cloud [144]

Answer:

\bar X \sim N(\mu=89, \frac{24}{\sqrt{64}}=3)

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

Let X the random variable of interest for a population. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =89,\sigma =24)

We take a sample of n=64 . That represent the sample size.

The sample mean is defined as:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And if we find the expected value and variance for the sample mean we got:

E(\bar X) = \mu

Var(\bar X) = \frac{\sigma^2}{n}[/tex]

The distribution for the sample mean is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=89, \frac{24}{\sqrt{64}}=3)

3 0
3 years ago
Gagagaaggagagaggagaga
elixir [45]
1.05,1.5,1.25 and 1.1, 1.05 is the smallest, so the answer should be Friday.
3 0
3 years ago
Read 2 more answers
Solve my question please, I’ll mark u as brainlest if the answer is correct and if you solved my question!!!
ikadub [295]

Answer:

x = price of balcony tickets = $7

y = price of orchestra tickets = $21

Step-by-step explanation:

Let

x = price of balcony tickets

y = price of orchestra tickets

y = 3x (1)

148y + 76x = 3,640 (2)

Substitute y = 3x into (2)

148y + 76x = 3,640 (2)

148(3x) + 76x = 3,640

444x + 76x = 3,640

520x = 3,640

x = 3,640/520

x = 7

Substitute x = 7 into (1)

y = 3x (1)

y = 3(7)

y = 21

x = price of balcony tickets = $7

y = price of orchestra tickets = $21

3 0
2 years ago
Two equations are given below:
goldenfox [79]
Since the second equation gives a value for a, we can substitute it into the other equation to find a value for B.

Let's substitute b-2 into the first equation wherever there is an a.

a - 3b = 4
(b-2) - 3b = 4
b - 2 - 3b = 4
-2 - 2b = 4
-2b = 6
b = -3

Now let's find a by substituting -3 into either of the equations to find the value of a.

a = b - 2
a = -3 - 2
a = -5

So your solution set  is (-5, -3)
4 0
3 years ago
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