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Makovka662 [10]

3 years ago

15

Answers for both boxes please

1 answer:

olga2289 [7]3 years ago

8 0

Answer:

?。*。?~?xXx

。?。*。Have。?

?。a wonderful day.

.?´*。.?¨¯`*❤。。?

Step-by-step explanation:

don't know sorry

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Rationalise the denominator of (12)/(\sqrt(10)+\sqrt(7)+\sqrt(3))

jasenka [17]

Answer:

$\frac{12}{\sqrt{10} +\sqrt{7} +\sqrt{3} }=\frac{6\sqrt{147} +6\sqrt{63}-6\sqrt{210} }{21 }$

Step-by-step explanation:

$\frac{12}{\sqrt{10} +\sqrt{7} +\sqrt{3} }$

$=\frac{12\left( \sqrt{10} -\left( \sqrt{7} +\sqrt{3} \right) \right) }{(\sqrt{10}+(\sqrt{7} +\sqrt{3 } ))( \sqrt{10} -( \sqrt{7} +\sqrt{3}))}$

$=\frac{12\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right) }{\sqrt{10^2} -(\sqrt{7} +\sqrt{3})^2}$

$\frac{12\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right) }{10-(10+2\sqrt{21} )} }$

$=\frac{12\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right) }{-2\sqrt{21} }$

$=\frac{-6\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right) }{\sqrt{21} }$

$=\frac{-6\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right) }{\sqrt{21} } \times\frac{\sqrt{21} }{\sqrt{21} }$

$=\frac{-6\sqrt{21} \left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right) }{21 }$

$=\frac{-6\sqrt{210} +6\sqrt{147} +6\sqrt{63} }{21 }$

$=\frac{6\sqrt{147} +6\sqrt{63}-6\sqrt{210} }{21 }$

<u><em>Remark</em></u>:

You can simplify moreover if you want to.

5 0

3 years ago

A rectangle's length is three times its width. Let w denote the rectangle's width. What polynomial represents the rectangle's pe

Nookie1986 [14]

L=3w

So, the perimeter will be,
P= 2L + 2w
P= 2(3w) + 2w
P= 6w + 2w
P= 8w units

6 0

3 years ago

Write an equation of a parabola that has two x-intercepts and a minimum vertex.

LuckyWell [14K]

B is correct ok yesssss

5 0

3 years ago

Read 2 more answers

SungHee empties her piggy bank and finds that that she has 200 quarters 150 dimes and 300 pennies. How much money does she have

gayaneshka [121]

A quarter = 0.25......200 quarters = 200(0.25) = $ 50
a dime = 0.10...150 dimes = 150(0.10) = $ 15
a penny = 0.01....300 pennies = 300(0.01) = $ 3

for a total of : 50 + 15 + 3 = $ 68

6 0

3 years ago

Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total

Gelneren [198K]

Answer : Sarah bought 4 first class tickets and 3 coach tickets.

Explanation :

We will call F the number of first class tickets and C the number of coach tickets.

Sarah had to buy a total of 7 tickets for 7 people.

Then F + C = 7 (Equation 1)

She used her total budget = $5,620

Then F*$1,150 + C*$340 = $5,620 (Equation 2)

F + C = 7

F = 7 - C

Now we can replace the value F in the equation 2

(7 - C)*$1,150 + C*$340 = $5,620

7*$1,150 - C*$1,150 + C*$340 = $5,620

$8,050 - C*$810 = $5,620

$8,050 - $5,620 = C*$810

$2,430 = C*$810

C = $2,430/$810 = 3 => number of coach tickets

F = 7 - C = 7 - 3 = 4 => number of first class tickets

Answer : Sarah bought 4 first class tickets and 3 coach tickets.

Verification

Replacing these values in equation 2

4*$1,150 + 3*$340 = $4,600 + $1,020 = $5620 => total budget

$\textit{\textbf{Spymore}}$

5 0

3 years ago