How many outer atoms and lone pairs are present in a molecule with a square pyramidal shape?
1 answer:
Answer:
5 Outer and 1 lone pair
Step-by-step explanation:
A square pyramidal shape results when one of the bonds of an octahedron structure is occupied by a lone pair.
Hence there are 5 bonded atoms and one lone pair. The hybridization about the central atom is .
One of the most common example is Xenon tetraflouride. . Looking at its structure we can see that it has 5 pairs of outer atoms and one lone pair. With its coordination number 5. The shape of the orbitals is octahedral.
You might be interested in
Answer:
There are no solutions for the pair of equations.
The lines are parallel to each other
Step-by-step explanation:
Line Q has a slope of 1/2 and crosses the y axis at 3.
This mean at x=0, y=3
Using the equation of a straight line expression to find the slope
y=mx +c where m is slope and c in the y intercept you can write the equation for Line Q as;
For the Line S , slope is 1/2 and the line crosses the y axis at -2 , which represents the c in the equation y=mx +c
The equation for S will be
Using the graphing tool to plot the two equations for line Q and line S we notice that the lines are parallel .For solutions, they have to intersect.
ANSWER
EXPLANATION
The quadratic equation is:
Group variable terms:
Add the square of half, the coefficient of y to both sides.
The LHS us now a perfect square trinomial:
Take square root:
The first choice is correct.