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Mariulka [41]
3 years ago
13

How many outer atoms and lone pairs are present in a molecule with a square pyramidal shape?

Mathematics
1 answer:
arlik [135]3 years ago
4 0

Answer:

5 Outer and 1 lone pair

Step-by-step explanation:

A square pyramidal shape results when one of the bonds of an octahedron structure is occupied by a lone pair.

Hence there are 5 bonded atoms and one lone pair. The hybridization about the central atom is sp^{3} d^2.

One of the most common example is Xenon tetraflouride. XeF_4. Looking at its structure we can see that it has 5 pairs of outer atoms and one lone pair. With its coordination number 5. The shape of the orbitals is octahedral.

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Answer:

(a) The mean and the standard deviation for the numbers of peas with green pods in the groups of 36 is 27 and 2.6 respectively.

(b) The significantly low values are those which are less than or equal to 21.8. And on the other hand, the significantly higher values are those which are greater than or equal to 32.2.

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Step-by-step explanation:

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(a) The mean of the binomial distribution is given by the product of sample size (n) and the probability (p), that is;

                    Mean, \mu  =  n \times p

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            Standard deviation, \sigma  =  \sqrt{n \times p \times (1-p)}

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(b) Now, the range rule of thumb states that the usual range of values lies within the 2 standard deviations of the mean, that means;

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          \mu + 2 \sigma  =  27 + (2 \times 2.6)

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(c) The result of 15 peas with green pods is a result that is a significantly​ low value because the value of 15 is less than 21.8 which is represented as a significantly low value.

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