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Mariulka [41]
3 years ago
13

How many outer atoms and lone pairs are present in a molecule with a square pyramidal shape?

Mathematics
1 answer:
arlik [135]3 years ago
4 0

Answer:

5 Outer and 1 lone pair

Step-by-step explanation:

A square pyramidal shape results when one of the bonds of an octahedron structure is occupied by a lone pair.

Hence there are 5 bonded atoms and one lone pair. The hybridization about the central atom is sp^{3} d^2.

One of the most common example is Xenon tetraflouride. XeF_4. Looking at its structure we can see that it has 5 pairs of outer atoms and one lone pair. With its coordination number 5. The shape of the orbitals is octahedral.

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Can someone please help me.... I need help with 43 muiltiplyed by 6 divedied by 2 simplafied to a frcation!
ddd [48]

Answer:

Your Answer will be 129, not a fraction. It will be a whole number

Step-by-step explanation:

43 x 6 = 258

258 / 2 = 129

5 0
3 years ago
Personal Finance: Cost of a Car The suggested list price of a new car is $24,000. The dealer’s cost is 85% of list. How much wil
RUDIKE [14]

Answer: $20,700

Step-by-step explanation:

Given that :

List price of car = $24,000

Dealer's cost = 85% of the list price of the car

Dealer acceptance cost = $300 over the cost

Hence, total amount to be paid :

Dealer's cost + dealer's acceptance cost

Dealer's cost = (0.85 * $24,000) = $21,400

Hence, Total cost :

$20,400 + $300 = $20,700

8 0
3 years ago
What value of c makes the polynomial below a perfect square? x2 10x c
Elden [556K]
X^2 + 10x + c

Use the number in front of x, (10), to help you.

First, divide 10 by 2:
10/2 = 5

Second, square the answer, (5).
(x+5)(x+5) = 25

Answer: c=+25
5 0
3 years ago
Help ASAP i havgt35axxqwr 7mins left to complete this
djyliett [7]

Answer:

what is the question here?

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Can you help me with this, please? ​
Aloiza [94]

Answer:

y =x-12

Step-by-step explanation:

(x_1, y_1) = (16, 4) \ \ \ and \ \ \ (x_2, y_2) = (17, 5)

Equation of straight line is

y-y_1 =\frac{y_2-y_1}{x_2-x_1}  (x-x_1)

y-4 =\frac{5-4}{17-16}  (x-16)

y =(x-16)+4

y =x-12

3 0
3 years ago
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