How many outer atoms and lone pairs are present in a molecule with a square pyramidal shape?
1 answer:
Answer:
5 Outer and 1 lone pair
Step-by-step explanation:
A square pyramidal shape results when one of the bonds of an octahedron structure is occupied by a lone pair.
Hence there are 5 bonded atoms and one lone pair. The hybridization about the central atom is .
One of the most common example is Xenon tetraflouride. . Looking at its structure we can see that it has 5 pairs of outer atoms and one lone pair. With its coordination number 5. The shape of the orbitals is octahedral.
You might be interested in
It depends on what you mean by the delimiting carats "^"...
Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for
.
In that case, you want to find the antiderivative,
Complete the square in the denominator:
Now substitute
, so that 
. Then
which simplifies to
Now, recall that
. But we want the substitution we made to be reversible, so that
which implies that
. (This is the range of the inverse sine function.)
Under these conditions, we have
, which lets us reduce 
. Finally,
and back-substituting to get this in terms of
yields
Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for
In that case, you want to find the antiderivative,
Complete the square in the denominator:
Now substitute
which simplifies to
Now, recall that
which implies that
Under these conditions, we have
and back-substituting to get this in terms of