How many outer atoms and lone pairs are present in a molecule with a square pyramidal shape?
1 answer:
Answer:
5 Outer and 1 lone pair
Step-by-step explanation:
A square pyramidal shape results when one of the bonds of an octahedron structure is occupied by a lone pair.
Hence there are 5 bonded atoms and one lone pair. The hybridization about the central atom is .
One of the most common example is Xenon tetraflouride. . Looking at its structure we can see that it has 5 pairs of outer atoms and one lone pair. With its coordination number 5. The shape of the orbitals is octahedral.
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Answer:
D(x) is a function
D(x) is a direct variation
D(x) is a rule for the set of points (5.10). (6, 12) and (-2,-4)
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form or
In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin
In this problem
D(x) is a direct variation (linear function)
The variable x is the independent variable or input value
The variable D(x) is the dependent variable or output value
<u><em>Verify each statement</em></u>
case 1) D(x) is a function
The statement is true
see the explanation
case 2) x is the dependent variable
The statement is false
The variable x is the independent variable or input value
case 3) D(x) is a direct variation
The statement is true
see the explanation
case 4) D(x) is a rule for the set of points (5.10). (6, 12) and (-2,-4)
The statement is true
Because
For x=5
substitute in the linear equation
---> is ok
For x=6
substitute in the linear equation
---> is ok
For x=-2
substitute in the linear equation
---> is ok