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3 years ago

What can be concluded about the relationship between the two functions?

1 answer:

5 0

<span>Both variables are categorical. We analyze an association through a comparison of conditional probabilities and graphically represent the data using contingency tables. Examples of categorical variables are gender and class standing.</span>

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On his outward journey, Ali travelled at a speed of s km/h for 2.5 hours. On his return journey, he increased his speed by 4 km/

den301095 [7]

Answer:

3.08 km/h.

Step-by-step explanation:

We know that,

$Speed=\dfrac{Distance}{Time}$

Ali traveled at a speed of s km/h for 2.5 hours.

Let d be the distance and t be the time.

$2.5=\dfrac{d}{t}$

$2.5t=d$ ...(1)

On his return journey, he increased his speed by 4 km/h and saved 15 minutes. So, distance is d and times is t-15.

$4=\dfrac{d}{t-15}$

$4(t-15)=d$ ...(2)

From (1) and (2), we get

$4(t-15)=2.5t$

$4t-60-2.5t=0$

$1.5t=60$

$t=40$

Put t=40 in (1).

$d=2.5(40)=100$

So, t=40 and d=100.

Now,

Total distance = d + d = 100 + 100 = 200

Total time = t + t - 15 = 40 + 40 - 15 = 65

So, the average speed is

$\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}$

$\text{Average speed}=\dfrac{200}{65}$

$\text{Average speed}\approx 3.08$

Therefore, the average speed is 3.08 km/h.

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4 years ago

A, B, C, OR D ?!?!??!?!?!?!?

nadezda [96]

The answer would be letter A

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3 years ago

What is the solution of x in the equation below ? -5(3-x)+4=5x-11

forsale [732]

All real numbers.
Explanation: any non imaginary number will work.

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4 years ago

A skateboarder is practicing in the city park. He is skating up and down the steepest straight-line ramp. If the highest point o

dalvyx [7]

C is the answer to your problem have a good day

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3 years ago

Order from least to greatest<br><br>1/8, 11/12, 9/8

zepelin [54]

Answer:

Step-by-step explanation:

First make the denominators the same.

Take the LCM of (8, 12 , 8) = 24

So,

$\frac{1}{8}, \frac{11}{12}, \frac{9}{8} \ becomes \ \frac{3}{24}, \frac{22}{24}, \frac{27}{24}$

$Order \ from \ least \ to \ greatest \ \\\\\frac{3}{24} < \frac{22}{24} < \frac{27}{24}$

That is,

$\frac{1}{8}, \frac{11}{12}, \frac{9}{8}$

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3 years ago