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3 years ago

Which equation represents a line that passes through (-9, -3) and has a slope of -6?

Mathematics

1 answer:

IRINA_888 [86]3 years ago

4 0

Answer:

y +3 = -6(x +9)

Step-by-step explanation:

The point-slope form of the equation of a line is ...

y -k = m(x -h)

for a line with slope m through point (h, k).

You want the line with slope -6 through point (-9, -3), so its equation is ...

y -(-3) = -6(x -(-9))

y +3 = -6(x +9) . . . . . matches the last choice

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Answer:

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Answer:

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Step-by-step explanation:

Given

$\begin{array}{cc}x & {f(x)} & -1&-9&0&-1&1&7 \ \end{array}$

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Solving (a): Compare the slopes

The slope (m) of f(x) is calculated as;

$m = \frac{f(x_2) - f(x_1)}{x_2 - x_1}$

This gives:

$m = \frac{f(0) - f(1)}{0 - 1}$

$m = \frac{f(0) - f(1)}{- 1}$

Substitute values for f(0) and f(1)

$m = \frac{-1 - 7}{- 1}$

$m = \frac{-8}{- 1}$

$m = 8$

The slope of g(x) can be gotten using the following comparison

$g(x) = mx + b$

$m \to slope$

So:

$g(x) = 3x -2$

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From the table of f(x)

$f(0) = -1$

From the equation of g(x)

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$g(0) =-2$

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Answer:

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Step-by-step explanation:

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