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Law Incorporation [45]
3 years ago
8

Help pls hello pls hello hello

Mathematics
2 answers:
ipn [44]3 years ago
5 0
Basically, we end up with a false statement like
0=3
or something like that
so simplfy each

A.
-5+8x-9=3(x+3)
8x-14=3x+9
minus 3x both sides
5x-14=9
add 15
5x=23
we see we will get a solution

B.
distribute
-12+6x=-12+6x
we can see there are infinite solutions

C.
6-2(3-2x)=-4(3-x)
6-6+4x=-12+4x
0+4x=-12+4x
minus 4x both sides
0=-12
false
here is our answer

C is the one with no solution
 
Novay_Z [31]3 years ago
5 0

Answer:

c has no answer...

have a great day!

Step-by-step explanation:

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Alina [70]

Answer:

10%

Step-by-step explanation:

5 0
3 years ago
Can someone help me with this math problem
Anton [14]

Answer:

$1,545

Step-by-step explanation:

3% of 1500 is 45

1500 + 45 = 1545

5 0
3 years ago
Find the absolute maximum and minimum of the function f(x,y) = x^2 + y^2 subject to the constraint x^4 + y^4 = 81. as usual, ign
borishaifa [10]
X^4+y^4=81

there are 2 solutions

x=0                   x=3
y=3       or          y=0
 
f(x,y)=3^2+0^2=9 is a constant who has the graph  a line || Ox 


8 0
3 years ago
What is the correct equilibrium constant expression for this equation? 2 upper C upper o upper F subscript 2 (g) double arrow up
Alekssandra [29.7K]

The correct equilibrium constant expression for this equation is;

\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}

Given

Consider the equation below.

\rm {2COF_2(g)}\rightleftharpoons C0_2(g)+CF_4(g)

<h3>What are Species?</h3>

In an equilibrium constant expression, you do not include the solid substances; only gases and dissolved substances.

<h3>Equilibrium constant expression;</h3>

It is the quotient of the product of the concentrations of the species on the right-hand side of the equilibrium equation, each raised to its corresponding coefficient, and the product of the concentrations of the species on the left-hand side, each raised to its corresponding coefficient.

Therefore,

The correct equilibrium constant expression for this equation is;

\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}

Hence, the correct equilibrium constant expression for this equation is;

\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}.

To know more about Equilibrium constant click the link is given below.

brainly.com/question/19240570

3 0
2 years ago
Write parametric equations of the line - 4x + y = -2
Anon25 [30]

Answer:

0-2 .1 +6

Step-by-step explanation:

4

x

+

y

=

−

2

Subtract  

4

x

from both sides of the equation.

y

=

−

2

−

4

x

Rewrite in slope-intercept form.

y

=

−

4

x

−

2

Use the slope-intercept form to find the slope and y-intercept.

Slope:  

−

4

y-intercept:  

−

2

Any line can be graphed using two points. Select two  

x

values, and plug them into the equation to find the corresponding  

y

values.

x

y

0

−

2

1

−

6

Graph the line using the slope and the y-intercept, or the points.

Slope:  

−

4

y-intercept:  

−

2

x

y

0

−

2

1

−

6

image of graph

4 0
3 years ago
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