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andrew11 [14]
3 years ago
15

If the sum of three consecutive odd integers is at most 216, what is the largest possible value of one of these integers?

Mathematics
1 answer:
Tpy6a [65]3 years ago
3 0
Since it is indicated that the sum of three consecutive odd integers is at most 216 and not exactly 216, the largest possible value of one of these integers is 73. The answer for this question would be option C. 69, 71, and 73 are the consecutive odd integers. Hope this answers your question.
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valkas [14]

Answer:

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Step-by-step explanation:

1. (7·7) - (7·9)

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Using the fixed-time period inventory model, and given an average daily demand of 200 units, 4 days between inventory reviews, 5
KATRIN_1 [288]

Answer:

Correct option: B. About 1,686.

Step-by-step explanation:

The formula to compute the order quantity (Q) is:

Q=(q_{d}\times (I+L))+(z\times\sigma_{I+L})-I_{n}

Here

q_{d}=average\ daily\ semand=200\\I = Inventory\ review\ time=4\\L=lead\ time=5\\\sigma_{I+L}=standard\ deviation\ over\ the\ review\ and\ lead\ time=3\\I_{n}=number\ of\ units\ of\ inventory\ on\ hand=120

Compute the order quantity as follows:

Q=(q_{d}\times (I+L))+(z\times\sigma_{I+L})-I_{n}\\=(200\times(4+5))+(1.96\times 3)-120\\=1800+5.88-120\\=1685.88\\\approx1686

Thus, the order quantity was about 1,686.

5 0
3 years ago
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Step-by-step explanation:

To find the mass of each bag, we divide 6 kg by 4.

(6 kg)/4 = 1.5 kg

Now we convert 1.5 kg to g.

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