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Delvig [45]
3 years ago
5

They’re 80 skittles in a bag 20% of them are read how many skittles a red

Mathematics
1 answer:
Nutka1998 [239]3 years ago
7 0

Answer: 16

Step-by-step explanation: 80x20=1600

Put the decimal place where it belongs

80% of 20=16

Hope this helps!

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If there are 7 blue chips and 5 red chips in a bag, what is the probability of drawing a blue chip?
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Answer:

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7/12

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How to work vector algebra
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Vectors and vector addition:

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Unit vectors:

A unit vector is a vector of unit length. A unit vector is sometimes denoted by replacing the arrow on a vector with a "^" or just adding a "^" on a boldfaced character (i.e., ). Therefore, Any vector can be made into a unit vector by dividing it by its length. Any vector can be fully represented by providing its magnitude and a unit vector along its direction.

Base vectors and vector components:

Base vectors are a set of vectors selected as a base to represent all other vectors. The idea is to construct each vector from the addition of vectors along the base directions. For example, the vector in the figure can be written as the sum of the three vectors u1, u2, and u3, each along the direction of one of the base vectors e1, e2, and e3, so that Each one of the vectors u1, u2, and u3 is parallel to one of the base vectors and can be written as scalar multiple of that base. Let u1, u2, and u3 denote these scalar multipliers such that one has<span> </span><span>The original vector</span><span> </span><span>u</span><span> </span><span>can now be written as </span><span>The scalar multipliers</span><span> </span><span>u</span><span>1</span><span>,</span><span> </span><span>u</span><span>2</span><span>, and</span><span> </span><span>u</span><span>3</span><span> </span><span>are known as the components of</span><span> </span><span>u</span><span> </span><span>in the base described by the base vectors</span><span> </span><span>e</span><span>1</span><span>,</span><span> </span><span>e</span><span>2</span><span>, and</span><span> </span><span>e</span><span>3</span><span>. If the base vectors are unit vectors, then the components represent the lengths, respectively, of the three vectors</span><span> </span><span>u</span><span>1</span><span>,</span><span> </span><span>u</span><span>2</span><span>, and</span><span> </span><span>u</span><span>3</span><span>. If the base vectors are unit vectors and are mutually orthogonal, then the base is known as an orthonormal, Euclidean, or Cartesian base.</span>

 

A vector can be resolved along any two directions in a plane containing it. The figure shows how the parallelogram rule is used to construct vectors a and b that add up to c. <span>In three dimensions, a vector can be resolved along any three non-coplanar lines. The figure shows how a vector can be resolved along the three directions by first finding a vector in the plane of two of the directions and then resolving this new vector along the two directions in the plane. </span><span>When vectors are represented in terms of base vectors and components, addition of two vectors results in the addition of the components of the vectors.</span>

8 0
3 years ago
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Using point-slope form, write an equation of the line that passes through (2,-1) and has a slope of -5
expeople1 [14]
Y – y1 = m(x – x1)

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5 0
3 years ago
Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b
poizon [28]

The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\

$&x=8+\sqrt{10}, x=8-\sqrt{10}

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0
1 year ago
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